To find the probability that a person with an iron deficiency is 20 years or older, given that we know the person has an iron deficiency, we need to follow these steps:
1. Identify the total number of people with an iron deficiency.
From the table, the total number of people with an iron deficiency across all age groups is given as [tex]\( 102 \)[/tex].
2. Identify the total number of people with an iron deficiency who are 20 years or older.
We need to add the number of people with an iron deficiency in the age groups 20-30 years and above 30 years. According to the table:
- Number of people with an iron deficiency aged 20-30 years is [tex]\( 37 \)[/tex].
- Number of people with an iron deficiency aged above 30 years is [tex]\( 24 \)[/tex].
So, the total number of people with an iron deficiency who are 20 years or older is:
[tex]\[
37 + 24 = 61
\][/tex]
3. Calculate the required probability.
The probability that a person with an iron deficiency is 20 years or older can be calculated by dividing the number of people with an iron deficiency who are 20 years or older by the total number of people with an iron deficiency:
[tex]\[
\text{Probability} = \frac{\text{Number of people with an iron deficiency who are 20 years or older}}{\text{Total number of people with an iron deficiency}}
\][/tex]
Plugging in the numbers:
[tex]\[
\text{Probability} = \frac{61}{102} \approx 0.60
\][/tex]
Thus, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\( 0.60 \)[/tex]. Therefore, the correct answer is:
C. [tex]\( 0.60 \)[/tex]
