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Sagot :
To determine the slope of the line given by the equation [tex]\( y = -3x + 2 \)[/tex], we need to look at the general form of a linear equation in the slope-intercept form, which is [tex]\( y = mx + b \)[/tex].
In this form:
- [tex]\( m \)[/tex] represents the slope of the line.
- [tex]\( b \)[/tex] represents the y-intercept (the point where the line crosses the y-axis).
For the equation [tex]\( y = -3x + 2 \)[/tex]:
- The coefficient of [tex]\( x \)[/tex] is [tex]\(-3\)[/tex].
This coefficient, [tex]\(-3\)[/tex], is the slope of the line.
Therefore, the slope of the line [tex]\( y = -3x + 2 \)[/tex] is:
A. [tex]\(-3\)[/tex]
In this form:
- [tex]\( m \)[/tex] represents the slope of the line.
- [tex]\( b \)[/tex] represents the y-intercept (the point where the line crosses the y-axis).
For the equation [tex]\( y = -3x + 2 \)[/tex]:
- The coefficient of [tex]\( x \)[/tex] is [tex]\(-3\)[/tex].
This coefficient, [tex]\(-3\)[/tex], is the slope of the line.
Therefore, the slope of the line [tex]\( y = -3x + 2 \)[/tex] is:
A. [tex]\(-3\)[/tex]
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