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Sagot :
Por supuesto, evaluaremos la función [tex]\( f(x) = 5x + 9 \)[/tex] en dos puntos: [tex]\( x = 1 \)[/tex] y [tex]\( x = \frac{1}{5} \)[/tex]. Vamos a hacerlo paso a paso:
1. Evaluación en [tex]\( x = 1 \)[/tex]:
Dada la función [tex]\( f(x) = 5x + 9 \)[/tex], sustituimos [tex]\( x = 1 \)[/tex] en la función:
[tex]\[ f(1) = 5(1) + 9 \][/tex]
Calculamos el resultado:
[tex]\[ f(1) = 5 + 9 = 14 \][/tex]
Entonces, la función evaluada en [tex]\( x = 1 \)[/tex] nos da [tex]\( f(1) = 14 \)[/tex].
2. Evaluación en [tex]\( x = \frac{1}{5} \)[/tex]:
Nuevamente usando la función [tex]\( f(x) = 5x + 9 \)[/tex], sustituimos [tex]\( x = \frac{1}{5} \)[/tex]:
[tex]\[ f\left( \frac{1}{5} \right) = 5 \left( \frac{1}{5} \right) + 9 \][/tex]
Simplificamos los términos:
[tex]\[ f\left( \frac{1}{5} \right) = 1 + 9 = 10 \][/tex]
Así, la función evaluada en [tex]\( x = \frac{1}{5} \)[/tex] nos da [tex]\( f\left( \frac{1}{5} \right) = 10.0 \)[/tex].
En resumen, los valores de la función [tex]\( f(x) = 5x + 9 \)[/tex] son:
- [tex]\( f(1) = 14 \)[/tex]
- [tex]\( f\left( \frac{1}{5} \right) = 10.0 \)[/tex]
1. Evaluación en [tex]\( x = 1 \)[/tex]:
Dada la función [tex]\( f(x) = 5x + 9 \)[/tex], sustituimos [tex]\( x = 1 \)[/tex] en la función:
[tex]\[ f(1) = 5(1) + 9 \][/tex]
Calculamos el resultado:
[tex]\[ f(1) = 5 + 9 = 14 \][/tex]
Entonces, la función evaluada en [tex]\( x = 1 \)[/tex] nos da [tex]\( f(1) = 14 \)[/tex].
2. Evaluación en [tex]\( x = \frac{1}{5} \)[/tex]:
Nuevamente usando la función [tex]\( f(x) = 5x + 9 \)[/tex], sustituimos [tex]\( x = \frac{1}{5} \)[/tex]:
[tex]\[ f\left( \frac{1}{5} \right) = 5 \left( \frac{1}{5} \right) + 9 \][/tex]
Simplificamos los términos:
[tex]\[ f\left( \frac{1}{5} \right) = 1 + 9 = 10 \][/tex]
Así, la función evaluada en [tex]\( x = \frac{1}{5} \)[/tex] nos da [tex]\( f\left( \frac{1}{5} \right) = 10.0 \)[/tex].
En resumen, los valores de la función [tex]\( f(x) = 5x + 9 \)[/tex] son:
- [tex]\( f(1) = 14 \)[/tex]
- [tex]\( f\left( \frac{1}{5} \right) = 10.0 \)[/tex]
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