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A cheetah goes from 0 m/s to 25 m/s in 2.5 s. What is the cheetah's rate of acceleration?

A. 0.10 m/s²
B. 6 m/s²
C. 10 m/s²
D. 25 m/s²

Sagot :

To determine the cheetah's rate of acceleration, we can use the formula for acceleration:

[tex]\[ a = \frac{{v_f - v_i}}{t} \][/tex]

where:
- [tex]\( a \)[/tex] is the acceleration,
- [tex]\( v_f \)[/tex] is the final velocity,
- [tex]\( v_i \)[/tex] is the initial velocity,
- [tex]\( t \)[/tex] is the time taken.

Let's break down the problem step-by-step:

1. Identify the given values:
- Initial velocity ([tex]\( v_i \)[/tex]) = 0 m/s
- Final velocity ([tex]\( v_f \)[/tex]) = 25 m/s
- Time ([tex]\( t \)[/tex]) = 2.5 seconds

2. Substitute the given values into the formula:
[tex]\[ a = \frac{{25 \ \text{m/s} - 0 \ \text{m/s}}}{2.5 \ \text{s}} \][/tex]

3. Calculate the acceleration:
[tex]\[ a = \frac{25 \ \text{m/s}}{2.5 \ \text{s}} \][/tex]
[tex]\[ a = 10 \ \text{m/s}^2 \][/tex]

Thus, the cheetah's rate of acceleration is [tex]\( 10 \ \text{m/s}^2 \)[/tex].

Therefore, the correct answer is:
C. [tex]\( 10 \ \text{m/s}^2 \)[/tex]
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