Sure! Let's calculate the molar mass of [tex]\( Al(OH)_3 \)[/tex] step-by-step.
### Step-by-Step Solution:
1. Identify the atomic masses from the periodic table:
- Aluminum (Al): 26.98 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.008 g/mol
2. Count the number of each type of atom in [tex]\( Al(OH)_3 \)[/tex]:
- Number of Aluminum (Al) atoms: 1
- Number of Oxygen (O) atoms: 3
- Number of Hydrogen (H) atoms: 3
3. Calculate the molar mass of each component:
- For Aluminum (Al):
[tex]\[
1 \times 26.98 \, \text{g/mol} = 26.98 \, \text{g/mol}
\][/tex]
- For Oxygen (O):
[tex]\[
3 \times 16.00 \, \text{g/mol} = 48.00 \, \text{g/mol}
\][/tex]
- For Hydrogen (H):
[tex]\[
3 \times 1.008 \, \text{g/mol} = 3.024 \, \text{g/mol}
\][/tex]
4. Sum all the molar masses to find the total molar mass of [tex]\( Al(OH)_3 \)[/tex]:
[tex]\[
26.98 \, \text{g/mol} + 48.00 \, \text{g/mol} + 3.024 \, \text{g/mol} = 78.004 \, \text{g/mol}
\][/tex]
Therefore, the molar mass of [tex]\( Al(OH)_3 \)[/tex] is:
[tex]\[
\boxed{78.004 \, \text{g/mol}}
\][/tex]
