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Given: [tex]\(\triangle RST \sim \triangle RYX\)[/tex] by the SSS similarity theorem.

Which ratio is also equal to [tex]\(\frac{RT}{RX}\)[/tex] and [tex]\(\frac{RS}{RY}\)[/tex]?

A. [tex]\(\frac{XY}{TS}\)[/tex]

B. [tex]\(\frac{SY}{RY}\)[/tex]

C. [tex]\(\frac{RX}{XT}\)[/tex]

D. [tex]\(\frac{ST}{YX}\)[/tex]


Sagot :

If [tex]\(\triangle RST\)[/tex] is similar to [tex]\(\triangle RYX\)[/tex] by the SSS (Side-Side-Side) similarity theorem, all corresponding sides of these similar triangles will have equal ratios.

Given:
[tex]\[ \frac{RT}{RX} = \frac{RS}{RY} \][/tex]
Since triangles are similar, the corresponding sides are proportional. The same ratio must apply to the third set of corresponding sides, which are [tex]\(ST\)[/tex] in [tex]\(\triangle RST\)[/tex] and [tex]\(XY\)[/tex] in [tex]\(\triangle RYX\)[/tex].

Thus, the ratio [tex]\(\frac{ST}{XY}\)[/tex] must also be equal to [tex]\(\frac{RT}{RX}\)[/tex] and [tex]\(\frac{RS}{RY}\)[/tex].

Therefore, the ratio that is also equal to [tex]\(\frac{RT}{RX}\)[/tex] and [tex]\(\frac{RS}{RY}\)[/tex] is:
[tex]\[ \frac{ST}{XY} \][/tex]

So, the correct answer is:
[tex]\[\boxed{\frac{S T}{X Y}}\][/tex]