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Given: g(x) = [tex]\sqrt{x} -4[/tex] and h(x) = 2x - 8

what are the restrictions on the domain of g*h

Sagot :

Answer:

[tex][0,+\infty)[/tex]

Step-by-step explanation:

Functions

Domain

A domain is the range of x values or input values that can be substituted for the x-terms in a function to produce a real value.

Restrictions are a set of x values that make a function produce an imaginary value.

[tex]\hrulefill[/tex]

Solving the Problem

The problem asks for the product's restriction, so we must identify the domains of g(x) and h(x).

The function h(x) = 2x - 8 is a linear function, thus its domain is all real numbers: [tex](-\infty,+\infty)[/tex].

The function g(x) = [tex]\sqrt x - 4[/tex] is a square root function, thus it does have a restriction.

Noticing the input value is under the radical means any x-values that make the radical undefined are a part of the restriction.

Knowing that all negative values make a radical undefined means that the domain, is [tex][0,+\infty)[/tex], this expresses that all non-negative values are suitable for g(x)'s domain.

Since there's a restriction for one of the functions, the product will have one too: [tex][0,+\infty)[/tex].

[tex]\dotfill[/tex]

Verification

This can be verified by graphing the product of g(x) and h(x), the domain of the function starts from 0 and goes in the positive infinity direction or rightwards.

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