At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

The table shows the elevation in feet that a hiker has yet to climb before reaching the peak in terms of the number of hours hiked.

\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] (hours) & [tex]$y$[/tex] (feet remaining) \\
\hline
2 & 1,400 \\
\hline
4 & 1,000 \\
\hline
\end{tabular}

In a function for this situation, the rate of change is [tex]$\qquad$[/tex] feet per hour, and the peak is at an elevation of [tex]$\qquad$[/tex] feet.

Sagot :

To solve the problem, let's determine the rate of change and the peak elevation step-by-step.

1. Identify the given data points:

We are given two points:
[tex]\[ (x_1, y_1) = (2, 1400) \quad \text{and} \quad (x_2, y_2) = (4, 1000) \][/tex]

2. Calculate the rate of change (slope):

The rate of change (slope) [tex]\( m \)[/tex] can be computed using the formula for the slope of a line between two points:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Plugging in the values:
[tex]\[ m = \frac{1000 - 1400}{4 - 2} = \frac{-400}{2} = -200 \text{ feet per hour} \][/tex]

3. Determine the linear equation:

The general form of the linear equation for this situation is [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] is the slope, and [tex]\( b \)[/tex] is the y-intercept (elevation at the peak when hours hiked is zero).

4. Find the y-intercept [tex]\( b \)[/tex]:

We will use one of the provided points and the slope to calculate [tex]\( b \)[/tex]. Using the point [tex]\( (2, 1400) \)[/tex], we substitute into the linear equation [tex]\( y = mx + b \)[/tex]:
[tex]\[ 1400 = (-200)(2) + b \][/tex]
[tex]\[ 1400 = -400 + b \][/tex]
[tex]\[ b = 1400 + 400 = 1800 \][/tex]

5. Conclusion:

The rate of change is [tex]\( -200 \)[/tex] feet per hour, and the peak is at an elevation of [tex]\( 1800 \)[/tex] feet.

Hence, in a function for this situation, the rate of change is [tex]\(-200\)[/tex] feet per hour and the peak is at an elevation of [tex]\( 1800 \)[/tex] feet.