Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Which of the following points are on the line given by the equation [tex]y = 5x[/tex]?

Check all that apply.

A. [tex]\((3, 6)\)[/tex]

B. [tex]\((3, 15)\)[/tex]

C. [tex]\((-1, -5)\)[/tex]

D. [tex]\((0, 1)\)[/tex]

E. [tex]\((4, 2)\)[/tex]

F. [tex]\((-1, 5)\)[/tex]

Sagot :

To determine which points lie on the line described by the equation [tex]\( y = 5x \)[/tex], we need to check each point individually by substituting the [tex]\( x \)[/tex] and [tex]\( y \)[/tex] values into the equation and verifying if the equation holds true.

Let's check each point one by one:

Point A: [tex]\((3, 6)\)[/tex]
- Substitute [tex]\( x = 3 \)[/tex] and [tex]\( y = 6 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot 3 = 15 \][/tex]
The given [tex]\( y \)[/tex] value is 6, so [tex]\( 6 \neq 15 \)[/tex]. This point is not on the line.

Point B: [tex]\((3, 15)\)[/tex]
- Substitute [tex]\( x = 3 \)[/tex] and [tex]\( y = 15 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot 3 = 15 \][/tex]
The given [tex]\( y \)[/tex] value is 15, so [tex]\( 15 = 15 \)[/tex]. This point is on the line.

Point C: [tex]\((-1, -5)\)[/tex]
- Substitute [tex]\( x = -1 \)[/tex] and [tex]\( y = -5 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot (-1) = -5 \][/tex]
The given [tex]\( y \)[/tex] value is -5, so [tex]\( -5 = -5 \)[/tex]. This point is on the line.

Point D: [tex]\((0, 1)\)[/tex]
- Substitute [tex]\( x = 0 \)[/tex] and [tex]\( y = 1 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot 0 = 0 \][/tex]
The given [tex]\( y \)[/tex] value is 1, so [tex]\( 1 \neq 0 \)[/tex]. This point is not on the line.

Point E: [tex]\((4, 2)\)[/tex]
- Substitute [tex]\( x = 4 \)[/tex] and [tex]\( y = 2 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot 4 = 20 \][/tex]
The given [tex]\( y \)[/tex] value is 2, so [tex]\( 2 \neq 20 \)[/tex]. This point is not on the line.

Point F: [tex]\((-1, 5)\)[/tex]
- Substitute [tex]\( x = -1 \)[/tex] and [tex]\( y = 5 \)[/tex] into the equation [tex]\( y = 5x \)[/tex]:
[tex]\[ y = 5 \cdot (-1) = -5 \][/tex]
The given [tex]\( y \)[/tex] value is 5, so [tex]\( 5 \neq -5 \)[/tex]. This point is not on the line.

To summarize, the points that lie on the line described by the equation [tex]\( y = 5x \)[/tex] are:

- B. [tex]\((3, 15)\)[/tex]
- C. [tex]\((-1, -5)\)[/tex]