Sure! Let's solve each of the given equations for [tex]\( x \)[/tex] step by step and round the answers to two decimal places.
### 10. [tex]\(\log_4 x = 3\)[/tex]
To solve this equation, we need to rewrite it in its exponential form:
[tex]\[
x = 4^3
\][/tex]
Now, calculate [tex]\( 4^3 \)[/tex]:
[tex]\[
4^3 = 64
\][/tex]
So, the solution is:
[tex]\[
x = 64
\][/tex]
### 11. [tex]\(\ln x = -2.5\)[/tex]
To solve this logarithmic equation, we need to rewrite it in its exponential form using the natural logarithm property:
[tex]\[
x = e^{-2.5}
\][/tex]
Calculate [tex]\( e^{-2.5} \)[/tex]:
[tex]\[
e^{-2.5} \approx 0.08
\][/tex]
So, the solution is:
[tex]\[
x \approx 0.08
\][/tex]
### 12. [tex]\(2 \cdot \log_3 x + 4 = 1\)[/tex]
First, isolate the logarithmic term:
[tex]\[
2 \cdot \log_3 x = 1 - 4
\][/tex]
[tex]\[
2 \cdot \log_3 x = -3
\][/tex]
Now, divide by 2:
[tex]\[
\log_3 x = -1.5
\][/tex]
Rewrite in its exponential form:
[tex]\[
x = 3^{-1.5}
\][/tex]
Calculate [tex]\( 3^{-1.5} \)[/tex]:
[tex]\[
3^{-1.5} \approx 0.19
\][/tex]
So, the solution is:
[tex]\[
x \approx 0.19
\][/tex]
### 13. [tex]\(10 \cdot \log (2x) = 30\)[/tex]
First, isolate the logarithmic term:
[tex]\[
\log (2x) = \frac{30}{10}
\][/tex]
[tex]\[
\log (2x) = 3
\][/tex]
Rewrite it in its exponential form:
[tex]\[
2x = 10^3
\][/tex]
Calculate [tex]\( 10^3 \)[/tex]:
[tex]\[
10^3 = 1000
\][/tex]
Now, solve for [tex]\( x \)[/tex]:
[tex]\[
2x = 1000 \implies x = \frac{1000}{2} = 500
\][/tex]
So, the solution is:
[tex]\[
x = 500.00
\][/tex]
### Summary
The solutions to the equations are:
10. [tex]\( x = 64 \)[/tex]
11. [tex]\( x \approx 0.08 \)[/tex]
12. [tex]\( x \approx 0.19 \)[/tex]
13. [tex]\( x = 500.00 \)[/tex]
