Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Ramanuj walked from "Tower A" to "Tower B" in the East for 10 feet. Then he turned to the right and walked 3 feet. Again, he turned to the right and walked 14 feet. How far is he from Tower A?

Sagot :

GinnyAnswer

Final answer:

Using the Pythagorean theorem, we find that Ramanuj is approximately 24.2 feet away from Tower A after walking east and north.


Explanation:

To find the distance from Tower A, we can use the concept of Pythagorean theorem in a right-angled triangle.

After walking 10 feet East, 3 feet North, and 14 feet East from Tower B, the horizontal distance from Tower A is 10 + 14 = 24 feet, and the vertical distance is 3 feet.

Therefore, the distance from Tower A is the hypotenuse of a right triangle with legs 24 feet and 3 feet, which can be calculated using the formula: distance = √(242 + 32) = √(576 + 9) = √585 = 24.2 feet(hypotenuse).


Learn more about Distance calculation using the Pythagorean theorem here:

https://brainly.com/question/29260362


Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.