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The town librarian bought a combination of new-release movies on DVD for [tex]$\$[/tex]20[tex]$ and classic movies on DVD for $[/tex]\[tex]$8$[/tex]. Let [tex]$x$[/tex] represent the number of new releases, and let [tex]$y$[/tex] represent the number of classics. If the librarian had a budget of [tex]$\$[/tex]500[tex]$ and wanted to purchase as many DVDs as possible, which values of $[/tex]x[tex]$ and $[/tex]y$ could represent the number of new-release and classic movies bought?

[tex]\[
\begin{array}{l}
x=8, \; y=45 \\
x=10, \; y=22 \\
x=16, \; y=22 \\
x=18, \; y=18
\end{array}
\][/tex]


Sagot :

To determine which values of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] fit within the librarian's budget and maximize the number of DVDs purchased, we can evaluate each combination provided. Remember, [tex]\( x \)[/tex] represents the number of new-release movies at [tex]\( \$20 \)[/tex] each and [tex]\( y \)[/tex] represents the number of classic movies at [tex]\( \$8 \)[/tex] each. The budget is [tex]\( \$500 \)[/tex].

We need to calculate the total expenditure for each combination and check if it is within the budget.

### Combination 1: [tex]\( x = 8 \)[/tex], [tex]\( y = 45 \)[/tex]

[tex]\[ \text{Total Cost} = (8 \times 20) + (45 \times 8) \][/tex]

[tex]\[ \text{Total Cost} = 160 + 360 = 520 \][/tex]

This combination exceeds the budget of [tex]\( \$500 \)[/tex].

### Combination 2: [tex]\( x = 10 \)[/tex], [tex]\( y = 22 \)[/tex]

[tex]\[ \text{Total Cost} = (10 \times 20) + (22 \times 8) \][/tex]

[tex]\[ \text{Total Cost} = 200 + 176 = 376 \][/tex]

This combination is within the budget of [tex]\( \$500 \)[/tex].

### Combination 3: [tex]\( x = 16 \)[/tex], [tex]\( y = 22 \)[/tex]

[tex]\[ \text{Total Cost} = (16 \times 20) + (22 \times 8) \][/tex]

[tex]\[ \text{Total Cost} = 320 + 176 = 496 \][/tex]

This combination is also within the budget of [tex]\( \$500 \)[/tex].

### Combination 4: [tex]\( x = 18 \)[/tex], [tex]\( y = 18 \)[/tex]

[tex]\[ \text{Total Cost} = (18 \times 20) + (18 \times 8) \][/tex]

[tex]\[ \text{Total Cost} = 360 + 144 = 504 \][/tex]

This combination exceeds the budget of [tex]\( \$500 \)[/tex].

### Conclusion

The combinations that fit within the [tex]\( \$500 \)[/tex] budget are:

- [tex]\( x = 10 \)[/tex], [tex]\( y = 22 \)[/tex] with a total cost of [tex]\( \$376 \)[/tex]
- [tex]\( x = 16 \)[/tex], [tex]\( y = 22 \)[/tex] with a total cost of [tex]\( \$496 \)[/tex]

Thus, the possible combinations that the librarian can afford are:

[tex]\[ (10, 22) \quad \text{and} \quad (16, 22) \][/tex]