Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To find the average atomic mass of an element with isotopes, you follow these steps:
1. Identify the atomic masses and their respective abundances.
- For isotope [tex]\( X-14 \)[/tex]:
- Atomic mass: 14.003 amu
- Abundance: 99.636%
- For isotope [tex]\( X-15 \)[/tex]:
- Atomic mass: 15.000 amu
- Abundance: 0.364%
2. Convert the abundances from percentages to fractions:
[tex]\[ \text{Abundance of } X-14 = \frac{99.636}{100} = 0.99636 \][/tex]
[tex]\[ \text{Abundance of } X-15 = \frac{0.364}{100} = 0.00364 \][/tex]
3. Multiply each atomic mass by its respective fractional abundance to find the contribution of each isotope to the average atomic mass:
[tex]\[ \text{Contribution of } X-14 = 14.003 \times 0.99636 = 13.95194668 \, \text{amu} \][/tex]
[tex]\[ \text{Contribution of } X-15 = 15.000 \times 0.00364 = 0.0546824 \, \text{amu} \][/tex]
4. Add the contributions of the isotopes to find the average atomic mass:
[tex]\[ \text{Average atomic mass} = 13.95194668 + 0.0546824 = 14.00662908 \, \text{amu} \][/tex]
5. Round the result to the nearest thousandth:
[tex]\[ \text{Average atomic mass} \approx 14.007 \, \text{amu} \][/tex]
Hence, the average atomic mass of element [tex]\( X \)[/tex] is [tex]\( 14.007 \, \text{amu} \)[/tex].
1. Identify the atomic masses and their respective abundances.
- For isotope [tex]\( X-14 \)[/tex]:
- Atomic mass: 14.003 amu
- Abundance: 99.636%
- For isotope [tex]\( X-15 \)[/tex]:
- Atomic mass: 15.000 amu
- Abundance: 0.364%
2. Convert the abundances from percentages to fractions:
[tex]\[ \text{Abundance of } X-14 = \frac{99.636}{100} = 0.99636 \][/tex]
[tex]\[ \text{Abundance of } X-15 = \frac{0.364}{100} = 0.00364 \][/tex]
3. Multiply each atomic mass by its respective fractional abundance to find the contribution of each isotope to the average atomic mass:
[tex]\[ \text{Contribution of } X-14 = 14.003 \times 0.99636 = 13.95194668 \, \text{amu} \][/tex]
[tex]\[ \text{Contribution of } X-15 = 15.000 \times 0.00364 = 0.0546824 \, \text{amu} \][/tex]
4. Add the contributions of the isotopes to find the average atomic mass:
[tex]\[ \text{Average atomic mass} = 13.95194668 + 0.0546824 = 14.00662908 \, \text{amu} \][/tex]
5. Round the result to the nearest thousandth:
[tex]\[ \text{Average atomic mass} \approx 14.007 \, \text{amu} \][/tex]
Hence, the average atomic mass of element [tex]\( X \)[/tex] is [tex]\( 14.007 \, \text{amu} \)[/tex].
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.