Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To solve the inequality [tex]\(\frac{(x+5)(x+1)}{x-4} \geq 0\)[/tex], we need to find the values of [tex]\(x\)[/tex] for which the expression is non-negative. We'll do this by following these steps:
1. Identify Critical Points: These are the values of [tex]\(x\)[/tex] where the numerator or denominator equals zero.
2. Determine Sign Changes: We need to examine the sign of the expression in each interval created by these critical points.
3. Construct the Solution: Based on the signs, we can determine the intervals where the expression is non-negative.
### 1. Identify Critical Points
Numerator:
[tex]\[ (x + 5)(x + 1) = 0 \][/tex]
This gives us two solutions:
[tex]\[ x + 5 = 0 \quad \Rightarrow \quad x = -5 \][/tex]
[tex]\[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \][/tex]
Denominator:
[tex]\[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \][/tex]
### 2. Determine Sign Changes
Now, we have the critical points: [tex]\(x = -5\)[/tex], [tex]\(x = -1\)[/tex], and [tex]\(x = 4\)[/tex]. These points divide the number line into four intervals:
- [tex]\( (-\infty, -5) \)[/tex]
- [tex]\( (-5, -1) \)[/tex]
- [tex]\( (-1, 4) \)[/tex]
- [tex]\( (4, \infty) \)[/tex]
We will test a point within each interval to determine whether the expression is positive or negative in that interval.
- For [tex]\(x < -5\)[/tex], pick [tex]\(x = -6\)[/tex]:
[tex]\[ \frac{(-6 + 5)(-6 + 1)}{-6 - 4} = \frac{(-1)(-5)}{-10} = \frac{5}{-10} = -0.5 \quad \text{(negative)} \][/tex]
- For [tex]\(-5 < x < -1\)[/tex], pick [tex]\(x = -3\)[/tex]:
[tex]\[ \frac{(-3 + 5)(-3 + 1)}{-3 - 4} = \frac{(2)(-2)}{-7} = \frac{-4}{-7} = \frac{4}{7} \quad \text{(positive)} \][/tex]
- For [tex]\(-1 < x < 4\)[/tex], pick [tex]\(x = 0\)[/tex]:
[tex]\[ \frac{(0 + 5)(0 + 1)}{0 - 4} = \frac{(5)(1)}{-4} = \frac{5}{-4} = -1.25 \quad \text{(negative)} \][/tex]
- For [tex]\(x > 4\)[/tex], pick [tex]\(x = 5\)[/tex]:
[tex]\[ \frac{(5 + 5)(5 + 1)}{5 - 4} = \frac{(10)(6)}{1} = 60 \quad \text{(positive)} \][/tex]
### 3. Construct the Solution
From our test points, we have determined that the expression is:
- Negative for [tex]\(x < -5\)[/tex]
- Positive for [tex]\(-5 < x < -1\)[/tex]
- Negative for [tex]\(-1 < x < 4\)[/tex]
- Positive for [tex]\(x > 4\)[/tex]
Finally, since we need [tex]\(\frac{(x+5)(x+1)}{x-4} \geq 0\)[/tex], we include the intervals where the expression is positive and also check if the critical points themselves are included:
- [tex]\(x = -5\)[/tex] and [tex]\(x = -1\)[/tex] make the numerator zero, thus satisfying the inequality.
- [tex]\(x = 4\)[/tex] makes the denominator zero, which must be excluded.
Therefore, the solution to the inequality is:
[tex]\[ -5 \leq x \leq -1 \][/tex]
1. Identify Critical Points: These are the values of [tex]\(x\)[/tex] where the numerator or denominator equals zero.
2. Determine Sign Changes: We need to examine the sign of the expression in each interval created by these critical points.
3. Construct the Solution: Based on the signs, we can determine the intervals where the expression is non-negative.
### 1. Identify Critical Points
Numerator:
[tex]\[ (x + 5)(x + 1) = 0 \][/tex]
This gives us two solutions:
[tex]\[ x + 5 = 0 \quad \Rightarrow \quad x = -5 \][/tex]
[tex]\[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \][/tex]
Denominator:
[tex]\[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \][/tex]
### 2. Determine Sign Changes
Now, we have the critical points: [tex]\(x = -5\)[/tex], [tex]\(x = -1\)[/tex], and [tex]\(x = 4\)[/tex]. These points divide the number line into four intervals:
- [tex]\( (-\infty, -5) \)[/tex]
- [tex]\( (-5, -1) \)[/tex]
- [tex]\( (-1, 4) \)[/tex]
- [tex]\( (4, \infty) \)[/tex]
We will test a point within each interval to determine whether the expression is positive or negative in that interval.
- For [tex]\(x < -5\)[/tex], pick [tex]\(x = -6\)[/tex]:
[tex]\[ \frac{(-6 + 5)(-6 + 1)}{-6 - 4} = \frac{(-1)(-5)}{-10} = \frac{5}{-10} = -0.5 \quad \text{(negative)} \][/tex]
- For [tex]\(-5 < x < -1\)[/tex], pick [tex]\(x = -3\)[/tex]:
[tex]\[ \frac{(-3 + 5)(-3 + 1)}{-3 - 4} = \frac{(2)(-2)}{-7} = \frac{-4}{-7} = \frac{4}{7} \quad \text{(positive)} \][/tex]
- For [tex]\(-1 < x < 4\)[/tex], pick [tex]\(x = 0\)[/tex]:
[tex]\[ \frac{(0 + 5)(0 + 1)}{0 - 4} = \frac{(5)(1)}{-4} = \frac{5}{-4} = -1.25 \quad \text{(negative)} \][/tex]
- For [tex]\(x > 4\)[/tex], pick [tex]\(x = 5\)[/tex]:
[tex]\[ \frac{(5 + 5)(5 + 1)}{5 - 4} = \frac{(10)(6)}{1} = 60 \quad \text{(positive)} \][/tex]
### 3. Construct the Solution
From our test points, we have determined that the expression is:
- Negative for [tex]\(x < -5\)[/tex]
- Positive for [tex]\(-5 < x < -1\)[/tex]
- Negative for [tex]\(-1 < x < 4\)[/tex]
- Positive for [tex]\(x > 4\)[/tex]
Finally, since we need [tex]\(\frac{(x+5)(x+1)}{x-4} \geq 0\)[/tex], we include the intervals where the expression is positive and also check if the critical points themselves are included:
- [tex]\(x = -5\)[/tex] and [tex]\(x = -1\)[/tex] make the numerator zero, thus satisfying the inequality.
- [tex]\(x = 4\)[/tex] makes the denominator zero, which must be excluded.
Therefore, the solution to the inequality is:
[tex]\[ -5 \leq x \leq -1 \][/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.