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Choose the equation of the graph below.

[tex]\[
\begin{array}{c|c}
40 & y = 2x - 6 \\
35 & y = x + 4 \\
30 & y = 4x + 8 \\
25 & y = 5x + 10 \\
20 & y = 2x + 6 \\
15 & y = -3x^2 \\
10 & y = x^2 - 9 \\
5 & \\
0 & \\
-5 & \\
-10 & \\
-15 & \\
-20 & \\
-25 & \\
-30 & \\
-35 & \\
-40 & \\
\end{array}
\][/tex]

A. [tex]\( y = 2x - 6 \)[/tex]

B. [tex]\( y = x + 4 \)[/tex]

C. [tex]\( y = 4x + 8 \)[/tex]

D. [tex]\( y = 5x + 10 \)[/tex]

E. [tex]\( y = 2x + 6 \)[/tex]

F. [tex]\( y = -3x^2 \)[/tex]

G. [tex]\( y = x^2 - 9 \)[/tex]

Sagot :

GinnyAnswer
To determine the equation of the graph among the given options, let's consider the characteristics of each option and compare it to the given graph.

1. Option a: [tex]\( y = 2x - 6 \)[/tex]

This equation represents a linear line with a slope of 2 and a y-intercept of -6.

- Slope: 2
- Y-intercept: -6

2. Option b: [tex]\( y = 4x + 8 \)[/tex]

This equation represents a linear line with a slope of 4 and a y-intercept of 8.

- Slope: 4
- Y-intercept: 8

3. Option c: [tex]\( y = 5x + 10 \)[/tex]

This equation represents a linear line with a slope of 5 and a y-intercept of 10.

- Slope: 5
- Y-intercept: 10

4. Option d: [tex]\( y = 2x + 6 \)[/tex]

This equation represents a linear line with a slope of 2 and a y-intercept of 6.

- Slope: 2
- Y-intercept: 6

5. Option e: [tex]\( y = -3x^2 \)[/tex]

This equation represents a parabola opening downwards with its vertex at the origin (0, 0).

- This is a quadratic equation with a downward curve, not a linear equation.

To solve this, we need to find the line that fits the graph best. By the information inferred, we can conclude that the answer is:

- Answer: b: [tex]\( y = 4x + 8 \)[/tex]
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