Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To determine the height at which a 6 kg weight is lifted to give it a gravitational potential energy of 70.56 joules, we can use the formula for gravitational potential energy:
[tex]\[ \text{Potential Energy} (PE) = \text{mass} (m) \times \text{gravitational acceleration} (g) \times \text{height} (h) \][/tex]
Given the values:
- Mass ([tex]\( m \)[/tex]) = 6 kg
- Gravitational acceleration ([tex]\( g \)[/tex]) = 9.8 m/s²
- Potential energy ([tex]\( PE \)[/tex]) = 70.56 J
We need to solve for the height ([tex]\( h \)[/tex]). Rearrange the formula to solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{\text{Potential Energy}}{\text{mass} \times \text{gravitational acceleration}} \][/tex]
Substitute the given values into the formula:
[tex]\[ h = \frac{70.56 \, \text{J}}{6 \, \text{kg} \times 9.8 \, \text{m/s}^2} \][/tex]
Simplify:
[tex]\[ h = \frac{70.56}{58.8} \][/tex]
[tex]\[ h = 1.2 \, \text{m} \][/tex]
Therefore, the height at which the 6 kg weight is lifted to give it 70.56 joules of gravitational potential energy is:
[tex]\[ \boxed{1.2 \, \text{m}} \][/tex]
So the correct answer is:
B. 1.2 m
[tex]\[ \text{Potential Energy} (PE) = \text{mass} (m) \times \text{gravitational acceleration} (g) \times \text{height} (h) \][/tex]
Given the values:
- Mass ([tex]\( m \)[/tex]) = 6 kg
- Gravitational acceleration ([tex]\( g \)[/tex]) = 9.8 m/s²
- Potential energy ([tex]\( PE \)[/tex]) = 70.56 J
We need to solve for the height ([tex]\( h \)[/tex]). Rearrange the formula to solve for [tex]\( h \)[/tex]:
[tex]\[ h = \frac{\text{Potential Energy}}{\text{mass} \times \text{gravitational acceleration}} \][/tex]
Substitute the given values into the formula:
[tex]\[ h = \frac{70.56 \, \text{J}}{6 \, \text{kg} \times 9.8 \, \text{m/s}^2} \][/tex]
Simplify:
[tex]\[ h = \frac{70.56}{58.8} \][/tex]
[tex]\[ h = 1.2 \, \text{m} \][/tex]
Therefore, the height at which the 6 kg weight is lifted to give it 70.56 joules of gravitational potential energy is:
[tex]\[ \boxed{1.2 \, \text{m}} \][/tex]
So the correct answer is:
B. 1.2 m
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.