Sure, let’s break down the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) step by step.
Step 1: Identify the reactants.
- We have hydrochloric acid (HCl) and sodium hydroxide (NaOH).
Step 2: Determine the type of reaction.
- This is a neutralization reaction because we are reacting an acid with a base.
Step 3: Write the chemical equation for the reaction.
- The general form for a neutralization reaction between an acid (HA) and a base (BOH) is:
[tex]\[ \text{HA} + \text{BOH} \rightarrow \text{BA} + \text{H}_2\text{O} \][/tex]
Step 4: Apply HCl and NaOH to this general form.
[tex]\[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \][/tex]
- Here, HCl is the acid and NaOH is the base.
- The products are sodium chloride (NaCl) and water ([tex]\( \text{H}_2\text{O} \)[/tex]).
Step 5: Identify the product.
- The product formed from the neutralization of HCl and NaOH is NaCl (sodium chloride).
Therefore, among the given options:
A. [tex]$ \text{NaCl} $[/tex]
B. [tex]$ \text{HClO}_4 $[/tex]
C. [tex]$ \text{NO}_2 $[/tex]
D. [tex]$ \text{Na}_2 \text{CO}_3 $[/tex]
Only option A, [tex]$ \text{NaCl} $[/tex], is the correct product of the reaction between hydrochloric acid and sodium hydroxide.
Conclusion:
The product of the reaction is sodium chloride, hence the correct answer is:
A. [tex]\( \text{NaCl} \)[/tex].
