Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Sure! Let's work through the problem step by step:
We are given two rational expressions:
[tex]\[ \frac{9x^2 + 3}{14x^2 - 9} \][/tex]
and
[tex]\[ \frac{-3x^2 + 11}{14x^2 - 9} \][/tex]
We need to subtract the second expression from the first. Since both denominators are the same, we can directly subtract the numerators:
[tex]\[ \frac{9x^2 + 3}{14x^2 - 9} - \frac{-3x^2 + 11}{14x^2 - 9} = \frac{(9x^2 + 3) - (-3x^2 + 11)}{14x^2 - 9} \][/tex]
Let's simplify the numerator:
[tex]\[ (9x^2 + 3) - (-3x^2 + 11) \][/tex]
Distribute the negative sign in the second part:
[tex]\[ 9x^2 + 3 + 3x^2 - 11 \][/tex]
Combine like terms:
[tex]\[ 9x^2 + 3x^2 + 3 - 11 = 12x^2 - 8 \][/tex]
So, the expression simplifies to:
[tex]\[ \frac{12x^2 - 8}{14x^2 - 9} \][/tex]
We can factor out a common factor from the numerator:
[tex]\[ 12x^2 - 8 = 4(3x^2 - 2) \][/tex]
Thus, we have:
[tex]\[ \frac{4(3x^2 - 2)}{14x^2 - 9} \][/tex]
So, the simplified form of the given subtraction is:
[tex]\[ \boxed{\frac{4(3x^2 - 2)}{14x^2 - 9}} \][/tex]
We are given two rational expressions:
[tex]\[ \frac{9x^2 + 3}{14x^2 - 9} \][/tex]
and
[tex]\[ \frac{-3x^2 + 11}{14x^2 - 9} \][/tex]
We need to subtract the second expression from the first. Since both denominators are the same, we can directly subtract the numerators:
[tex]\[ \frac{9x^2 + 3}{14x^2 - 9} - \frac{-3x^2 + 11}{14x^2 - 9} = \frac{(9x^2 + 3) - (-3x^2 + 11)}{14x^2 - 9} \][/tex]
Let's simplify the numerator:
[tex]\[ (9x^2 + 3) - (-3x^2 + 11) \][/tex]
Distribute the negative sign in the second part:
[tex]\[ 9x^2 + 3 + 3x^2 - 11 \][/tex]
Combine like terms:
[tex]\[ 9x^2 + 3x^2 + 3 - 11 = 12x^2 - 8 \][/tex]
So, the expression simplifies to:
[tex]\[ \frac{12x^2 - 8}{14x^2 - 9} \][/tex]
We can factor out a common factor from the numerator:
[tex]\[ 12x^2 - 8 = 4(3x^2 - 2) \][/tex]
Thus, we have:
[tex]\[ \frac{4(3x^2 - 2)}{14x^2 - 9} \][/tex]
So, the simplified form of the given subtraction is:
[tex]\[ \boxed{\frac{4(3x^2 - 2)}{14x^2 - 9}} \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.