Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To simplify the expression [tex]\(\log_a(\sqrt{2}) + \log_a(8) + \log_a\left(\frac{1}{2}\right)\)[/tex] and express it in the form [tex]\(p \log_a(2)\)[/tex], we can use logarithm properties. Let's break it down step-by-step:
1. Simplify [tex]\(\log_a(\sqrt{2})\)[/tex]:
- Recall that [tex]\(\sqrt{2} = 2^{1/2}\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^{1/2}) = \frac{1}{2} \log_a(2)\)[/tex].
- So, [tex]\(\log_a(\sqrt{2}) = \frac{1}{2} \log_a(2)\)[/tex].
2. Simplify [tex]\(\log_a(8)\)[/tex]:
- Recall that [tex]\(8 = 2^3\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^3) = 3 \log_a(2)\)[/tex].
- So, [tex]\(\log_a(8) = 3 \log_a(2)\)[/tex].
3. Simplify [tex]\(\log_a\left(\frac{1}{2}\right)\)[/tex]:
- Recall that [tex]\(\frac{1}{2} = 2^{-1}\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^{-1}) = -\log_a(2)\)[/tex].
- So, [tex]\(\log_a\left(\frac{1}{2}\right) = -\log_a(2)\)[/tex].
Now we combine all the simplified expressions:
[tex]\[ \begin{align*} \log_a(\sqrt{2}) + \log_a(8) + \log_a\left(\frac{1}{2}\right) &= \frac{1}{2} \log_a(2) + 3 \log_a(2) - \log_a(2)\\ &= \left(\frac{1}{2} + 3 - 1\right) \log_a(2)\\ &= \left(\frac{1}{2} + 2\right) \log_a(2)\\ &= \left(\frac{1}{2} + \frac{4}{2}\right) \log_a(2)\\ &= \left(\frac{5}{2}\right) \log_a(2). \end{align*} \][/tex]
Thus, the expression simplifies to:
[tex]\[ \frac{5}{2} \log_a(2). \][/tex]
Therefore, in the form [tex]\(p \log_a(2)\)[/tex], we have [tex]\(p = \frac{5}{2}\)[/tex].
1. Simplify [tex]\(\log_a(\sqrt{2})\)[/tex]:
- Recall that [tex]\(\sqrt{2} = 2^{1/2}\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^{1/2}) = \frac{1}{2} \log_a(2)\)[/tex].
- So, [tex]\(\log_a(\sqrt{2}) = \frac{1}{2} \log_a(2)\)[/tex].
2. Simplify [tex]\(\log_a(8)\)[/tex]:
- Recall that [tex]\(8 = 2^3\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^3) = 3 \log_a(2)\)[/tex].
- So, [tex]\(\log_a(8) = 3 \log_a(2)\)[/tex].
3. Simplify [tex]\(\log_a\left(\frac{1}{2}\right)\)[/tex]:
- Recall that [tex]\(\frac{1}{2} = 2^{-1}\)[/tex].
- By the power rule of logarithms, [tex]\(\log_a(2^{-1}) = -\log_a(2)\)[/tex].
- So, [tex]\(\log_a\left(\frac{1}{2}\right) = -\log_a(2)\)[/tex].
Now we combine all the simplified expressions:
[tex]\[ \begin{align*} \log_a(\sqrt{2}) + \log_a(8) + \log_a\left(\frac{1}{2}\right) &= \frac{1}{2} \log_a(2) + 3 \log_a(2) - \log_a(2)\\ &= \left(\frac{1}{2} + 3 - 1\right) \log_a(2)\\ &= \left(\frac{1}{2} + 2\right) \log_a(2)\\ &= \left(\frac{1}{2} + \frac{4}{2}\right) \log_a(2)\\ &= \left(\frac{5}{2}\right) \log_a(2). \end{align*} \][/tex]
Thus, the expression simplifies to:
[tex]\[ \frac{5}{2} \log_a(2). \][/tex]
Therefore, in the form [tex]\(p \log_a(2)\)[/tex], we have [tex]\(p = \frac{5}{2}\)[/tex].
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.