At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Part 1 - Class Work (20 points)

Determine whether the point [tex]\((2, -3)\)[/tex] is on the graph of the equation [tex]\(x + y = 1\)[/tex].


Sagot :

To determine whether the point [tex]\((2, -3)\)[/tex] is on the graph of the equation [tex]\(x + y = 1\)[/tex], we need to substitute the coordinates of the point into the equation and verify if the equation holds true.

Let's go through this step-by-step:

1. Substitute the x-coordinate: In the equation [tex]\(x + y = 1\)[/tex], substitute [tex]\(x\)[/tex] with 2.
[tex]\[ 2 + y = 1 \][/tex]

2. Substitute the y-coordinate: In the same equation, substitute [tex]\(y\)[/tex] with -3.
[tex]\[ 2 + (-3) = 1 \][/tex]

3. Simplify the left-hand side: Perform the arithmetic operation on the left-hand side.
[tex]\[ 2 - 3 = -1 \][/tex]

4. Compare to the right-hand side: Check whether the simplified left-hand side is equal to the right-hand side.
[tex]\[ -1 = 1 \quad \text{(This is not true)} \][/tex]

Since [tex]\(-1\)[/tex] is not equal to [tex]\(1\)[/tex], the equation [tex]\(2 + (-3) = 1\)[/tex] does not hold true.

Therefore, the point [tex]\((2, -3)\)[/tex] is not on the graph of the equation [tex]\(x + y = 1\)[/tex].
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.