Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To determine whether the point [tex]\((2, -3)\)[/tex] is on the graph of the equation [tex]\(x + y = 1\)[/tex], we need to substitute the coordinates of the point into the equation and verify if the equation holds true.
Let's go through this step-by-step:
1. Substitute the x-coordinate: In the equation [tex]\(x + y = 1\)[/tex], substitute [tex]\(x\)[/tex] with 2.
[tex]\[ 2 + y = 1 \][/tex]
2. Substitute the y-coordinate: In the same equation, substitute [tex]\(y\)[/tex] with -3.
[tex]\[ 2 + (-3) = 1 \][/tex]
3. Simplify the left-hand side: Perform the arithmetic operation on the left-hand side.
[tex]\[ 2 - 3 = -1 \][/tex]
4. Compare to the right-hand side: Check whether the simplified left-hand side is equal to the right-hand side.
[tex]\[ -1 = 1 \quad \text{(This is not true)} \][/tex]
Since [tex]\(-1\)[/tex] is not equal to [tex]\(1\)[/tex], the equation [tex]\(2 + (-3) = 1\)[/tex] does not hold true.
Therefore, the point [tex]\((2, -3)\)[/tex] is not on the graph of the equation [tex]\(x + y = 1\)[/tex].
Let's go through this step-by-step:
1. Substitute the x-coordinate: In the equation [tex]\(x + y = 1\)[/tex], substitute [tex]\(x\)[/tex] with 2.
[tex]\[ 2 + y = 1 \][/tex]
2. Substitute the y-coordinate: In the same equation, substitute [tex]\(y\)[/tex] with -3.
[tex]\[ 2 + (-3) = 1 \][/tex]
3. Simplify the left-hand side: Perform the arithmetic operation on the left-hand side.
[tex]\[ 2 - 3 = -1 \][/tex]
4. Compare to the right-hand side: Check whether the simplified left-hand side is equal to the right-hand side.
[tex]\[ -1 = 1 \quad \text{(This is not true)} \][/tex]
Since [tex]\(-1\)[/tex] is not equal to [tex]\(1\)[/tex], the equation [tex]\(2 + (-3) = 1\)[/tex] does not hold true.
Therefore, the point [tex]\((2, -3)\)[/tex] is not on the graph of the equation [tex]\(x + y = 1\)[/tex].
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.