At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Draw the Lewis electron dot structure for [tex]$H_3O^+$[/tex].

What is the VSEPR shape of this particle?


Sagot :

Final answer:

The Lewis structure for H3O+ involves one oxygen atom and three hydrogen atoms, with a total of 9 valence electrons. The VSEPR shape of H3O+ is trigonal pyramidal due to the electron geometry and molecular shape.


Explanation:

Lewis Electron Dot Structure for H3O+: The Lewis structure for H3O+ consists of one oxygen atom with three hydrogen atoms attached to it. Oxygen has 6 valence electrons, and each hydrogen contributes one, making a total of 9 valence electrons. The structure will have three lone pairs on oxygen and three single bonds to hydrogen.

VSEPR Shape of H3O+: The VSEPR shape of H3O+ is trigonal pyramidal. In this shape, the oxygen atom is at the center, with three bonding pairs and one lone pair of electrons, creating a tetrahedral electron geometry and a trigonal pyramidal molecular shape.


Learn more about Lewis Electron Dot Structure and VSEPR Shape here:

https://brainly.com/question/41162072