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What value of [tex]$x$[/tex] satisfies this equation?
[tex]1.5(x^2) = 12[/tex]

Round your answer to the nearest hundredth.

The value of [tex]$x$[/tex] is [tex]$\square$[/tex]


Sagot :

To solve the equation

[tex]\[ 1.5 \cdot (4x)^2 = 12 \][/tex]

we follow these steps:

1. Simplify the equation:

Divide both sides of the equation by 1.5 to isolate the term involving [tex]\(x\)[/tex]:

[tex]\[ (4x)^2 = \frac{12}{1.5} \][/tex]

2. Compute the right side:

[tex]\[ \frac{12}{1.5} = 8 \][/tex]

So the equation now reads:

[tex]\[ (4x)^2 = 8 \][/tex]

3. Take the square root of both sides:

[tex]\[ 4x = \sqrt{8} \][/tex]

4. Isolate [tex]\(x\)[/tex]:

Divide both sides by 4:

[tex]\[ x = \frac{\sqrt{8}}{4} \][/tex]

5. Simplify the expression:

Recognize that [tex]\(\sqrt{8}\)[/tex] can be simplified as [tex]\(\sqrt{4 \cdot 2} = 2\sqrt{2}\)[/tex]:

[tex]\[ x = \frac{2\sqrt{2}}{4} = \frac{\sqrt{2}}{2} \][/tex]

Using a calculator, the approximate value of [tex]\(\frac{\sqrt{2}}{2}\)[/tex] is 0.7071067811865476.

6. Round to the nearest hundredth:

[tex]\[ x \approx 0.71 \][/tex]

The value of [tex]\(x\)[/tex] that satisfies the given equation, rounded to the nearest hundredth, is

[tex]\(\boxed{0.71}\)[/tex].