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In which triangle is the value of [tex]x[/tex] equal to [tex]\tan^{-1}\left(\frac{3.1}{5.2}\right)[/tex]?

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Sagot :

To determine in which triangle the value of [tex]\( x \)[/tex] is equal to [tex]\( \tan^{-1} \left( \frac{3.1}{5.2} \right) \)[/tex], we need to understand the relationship given by the arctangent function.

### Step-by-Step Solution:

1. Understand the Problem:
- We're given an angle [tex]\( x \)[/tex] defined as [tex]\( \tan^{-1} \left( \frac{3.1}{5.2} \right) \)[/tex].
- This means that in a right triangle, [tex]\( x \)[/tex] is the angle whose tangent is the ratio of the lengths of the opposite side to the adjacent side, which is [tex]\( \frac{3.1}{5.2} \)[/tex].

2. Calculate the Angle:
- The angle [tex]\( x \)[/tex] can be computed using the arctangent function, which retrieves the angle for a given tangent value.
- In this specific case, [tex]\( x \approx 0.5376 \)[/tex] radians.
- Converting this angle from radians to degrees (as typically angles in geometry are in degrees), we get [tex]\( x \approx 30.80^\circ \)[/tex].

3. Relate to Triangle Properties:
- For an angle [tex]\( x \)[/tex] in a right triangle:
[tex]\[ \tan(x) = \frac{\text{opposite}}{\text{adjacent}} \][/tex]
- Given:
[tex]\[ \tan(x) = \frac{3.1}{5.2} \][/tex]

4. Check the Given Options:
- Each triangle will have sides labeled with lengths corresponding to the opposite and adjacent sides from the angle [tex]\( x \)[/tex].
- To find the correct triangle, we simply find one where the ratio of the lengths of these sides matches [tex]\( \frac{3.1}{5.2} \)[/tex].

5. Conclusion:
- The correct triangle has an angle [tex]\( x \)[/tex] such that the sides opposite and adjacent to [tex]\( x \)[/tex] have lengths 3.1 and 5.2, respectively.
- Therefore, the angle [tex]\( x \)[/tex] in this triangle will be approximately [tex]\( 30.80^\circ \)[/tex].

### Final Answer:
The correct triangle is the one where the ratio of the length of the opposite side to the adjacent side to angle [tex]\( x \)[/tex] is [tex]\( \frac{3.1}{5.2} \)[/tex]. This corresponds to the angle [tex]\( x \approx 30.80^\circ \)[/tex].