Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To solve the problem of finding the area of the right triangle, we need to use the given angle and the base length. Here's a step-by-step breakdown of the solution:
1. Identify the given values:
- One angle of the right triangle is [tex]\(23^\circ\)[/tex].
- The length of the base [tex]\( b \)[/tex] is 30 cm.
2. Determine the height using trigonometric properties:
- Since the angle given is [tex]\(23^\circ\)[/tex] and it is the angle adjacent to the base, we use the tangent function. The tangent of an angle in a right triangle is the ratio of the opposite side (which will be the height [tex]\( h \)[/tex]) to the adjacent side (which is the base [tex]\( b \)[/tex]).
- Therefore, [tex]\(\tan(23^\circ) = \frac{h}{b}\)[/tex].
3. Calculate the height:
- Rearrange the equation to solve for [tex]\( h \)[/tex]: [tex]\( h = b \times \tan(23^\circ) \)[/tex].
- Substitute [tex]\( b = 30 \)[/tex] cm into the equation: [tex]\( h = 30 \cdot \tan(23^\circ) \)[/tex].
- Using the tangent value: [tex]\( \tan(23^\circ) \approx 0.424 \)[/tex].
- Thus, [tex]\( h = 30 \times 0.424 \approx 12.734244486288143 \)[/tex] cm.
4. Calculate the area of the triangle:
- The formula for the area of a triangle is [tex]\( \text{Area} = \frac{1}{2} \cdot b \cdot h \)[/tex].
- Substitute the values: [tex]\( \text{Area} = \frac{1}{2} \cdot 30 \cdot 12.734244486288143 \)[/tex].
- Perform the calculation: [tex]\( \text{Area} = 191.01366729432215 \)[/tex] cm[tex]\(^2\)[/tex].
5. Approximate and choose the closest value:
- The calculated area is approximately [tex]\( 191.01 \)[/tex] cm[tex]\(^2\)[/tex].
Comparing this to the given choices:
- [tex]\( 68.7 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 381.3 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 450.0 \)[/tex] cm[tex]\(^2\)[/tex]
The closest value to [tex]\( 191.01 \)[/tex] cm[tex]\(^2\)[/tex] is [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex].
Therefore, the approximate area of the triangle is [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex].
1. Identify the given values:
- One angle of the right triangle is [tex]\(23^\circ\)[/tex].
- The length of the base [tex]\( b \)[/tex] is 30 cm.
2. Determine the height using trigonometric properties:
- Since the angle given is [tex]\(23^\circ\)[/tex] and it is the angle adjacent to the base, we use the tangent function. The tangent of an angle in a right triangle is the ratio of the opposite side (which will be the height [tex]\( h \)[/tex]) to the adjacent side (which is the base [tex]\( b \)[/tex]).
- Therefore, [tex]\(\tan(23^\circ) = \frac{h}{b}\)[/tex].
3. Calculate the height:
- Rearrange the equation to solve for [tex]\( h \)[/tex]: [tex]\( h = b \times \tan(23^\circ) \)[/tex].
- Substitute [tex]\( b = 30 \)[/tex] cm into the equation: [tex]\( h = 30 \cdot \tan(23^\circ) \)[/tex].
- Using the tangent value: [tex]\( \tan(23^\circ) \approx 0.424 \)[/tex].
- Thus, [tex]\( h = 30 \times 0.424 \approx 12.734244486288143 \)[/tex] cm.
4. Calculate the area of the triangle:
- The formula for the area of a triangle is [tex]\( \text{Area} = \frac{1}{2} \cdot b \cdot h \)[/tex].
- Substitute the values: [tex]\( \text{Area} = \frac{1}{2} \cdot 30 \cdot 12.734244486288143 \)[/tex].
- Perform the calculation: [tex]\( \text{Area} = 191.01366729432215 \)[/tex] cm[tex]\(^2\)[/tex].
5. Approximate and choose the closest value:
- The calculated area is approximately [tex]\( 191.01 \)[/tex] cm[tex]\(^2\)[/tex].
Comparing this to the given choices:
- [tex]\( 68.7 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 381.3 \)[/tex] cm[tex]\(^2\)[/tex]
- [tex]\( 450.0 \)[/tex] cm[tex]\(^2\)[/tex]
The closest value to [tex]\( 191.01 \)[/tex] cm[tex]\(^2\)[/tex] is [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex].
Therefore, the approximate area of the triangle is [tex]\( 161.8 \)[/tex] cm[tex]\(^2\)[/tex].
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.