At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Determining the Possible Steps for Solving a Quadratic Equation by Completing the Square

Which are steps that could be used to solve [tex]0=9\left(x^2+6x\right)-18[/tex] by completing the square? Check all that apply.

A. [tex]18 + 81 = 9\left(x^2 + 6x + 9\right)[/tex]
B. [tex]18 + 9 = 9\left(x^2 + 6x + 9\right)[/tex]
C. [tex]18 + 36 = 9\left(x^2 + 6x + 36\right)[/tex]
D. [tex]11 = (x + 3)^2[/tex]
E. [tex]\sqrt{342} = (x + 6)^2[/tex]
F. [tex]\sqrt{99} = (x + 3)^2[/tex]


Sagot :

To solve the quadratic equation [tex]\(0 = 9(x^2 + 6x) - 18\)[/tex] by completing the square, we can follow these steps:

1. Distribute the 9 and move the constant to the other side of the equation:
[tex]\[ 0 = 9(x^2 + 6x) - 18 \][/tex]
Add 18 to both sides:
[tex]\[ 18 = 9(x^2 + 6x) \][/tex]

2. Divide by 9 on both sides to simplify:
[tex]\[ \frac{18}{9} = x^2 + 6x \][/tex]
[tex]\[ 2 = x^2 + 6x \][/tex]

3. Complete the square on the right-hand side:
To complete the square, take half of the coefficient of [tex]\(x\)[/tex] (which is 6), square it, and add it to both sides:
[tex]\[ 2 + 9 = x^2 + 6x + 9 \][/tex]
[tex]\[ 11 = (x + 3)^2 \][/tex]

4. Solve the resulting equation by taking the square root of both sides:
[tex]\[ \sqrt{11} = x + 3 \][/tex]
Therefore,
[tex]\[ x = \sqrt{11} - 3 \][/tex]
or
[tex]\[ x = -\sqrt{11} - 3 \][/tex]

Given the provided options, we can identify the steps that are valid and correspond to the correct procedure:

- [tex]\(18=9(x^2+6x)\)[/tex]
- [tex]\(18+9 = 9(x^2 + 6x + 9)\)[/tex] (completing the square using [tex]\((6/2)^2 = 9\)[/tex])
- [tex]\(11 = (x + 3)^2\)[/tex] (reflects the square completion correctly)

Therefore, the valid steps are:

[tex]\[ \boxed{18 + 9 = 9(x^2 + 6x + 9)} \][/tex]
[tex]\[ \boxed{11 = (x + 3)^2} \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.