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Sagot :
To determine the probability that a person with an iron deficiency is aged 20 years or older, we need to follow these steps:
1. Identify the total number of people with an iron deficiency:
This information is provided in the table under the "Yes" row in the "Total" column.
[tex]\[ \text{Total number of people with iron deficiency} = 102 \][/tex]
2. Calculate the number of people with an iron deficiency who are 20 years or older:
This includes people in the age groups 20-30 and above 30.
[tex]\[ \text{Number of people aged 20-30 with iron deficiency} = 37 \][/tex]
[tex]\[ \text{Number of people aged above 30 with iron deficiency} = 24 \][/tex]
Adding these values together:
[tex]\[ \text{Number of people aged 20 or older with iron deficiency} = 37 + 24 = 61 \][/tex]
3. Calculate the probability:
The probability is calculated by dividing the number of people aged 20 or older with an iron deficiency by the total number of people with an iron deficiency.
[tex]\[ \text{Probability} = \frac{\text{Number of people aged 20 or older with iron deficiency}}{\text{Total number of people with iron deficiency}} = \frac{61}{102} \][/tex]
[tex]\[ \text{Probability} \approx 0.598 \][/tex]
So, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\( 0.60 \)[/tex].
Thus, the correct answer is:
C. [tex]\( 0.60 \)[/tex]
1. Identify the total number of people with an iron deficiency:
This information is provided in the table under the "Yes" row in the "Total" column.
[tex]\[ \text{Total number of people with iron deficiency} = 102 \][/tex]
2. Calculate the number of people with an iron deficiency who are 20 years or older:
This includes people in the age groups 20-30 and above 30.
[tex]\[ \text{Number of people aged 20-30 with iron deficiency} = 37 \][/tex]
[tex]\[ \text{Number of people aged above 30 with iron deficiency} = 24 \][/tex]
Adding these values together:
[tex]\[ \text{Number of people aged 20 or older with iron deficiency} = 37 + 24 = 61 \][/tex]
3. Calculate the probability:
The probability is calculated by dividing the number of people aged 20 or older with an iron deficiency by the total number of people with an iron deficiency.
[tex]\[ \text{Probability} = \frac{\text{Number of people aged 20 or older with iron deficiency}}{\text{Total number of people with iron deficiency}} = \frac{61}{102} \][/tex]
[tex]\[ \text{Probability} \approx 0.598 \][/tex]
So, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\( 0.60 \)[/tex].
Thus, the correct answer is:
C. [tex]\( 0.60 \)[/tex]
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