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The low temperature in Leroy's town one day was [tex]$-4^{\circ}F$[/tex]. The difference between the high temperature and the low temperature that day was [tex]$6^{\circ}$[/tex].

The equation [tex][tex]$h - (-4) = 6$[/tex][/tex] can be used to find [tex]$h$[/tex], the high temperature in the town that day in degrees Fahrenheit.

What was the high temperature in the town that day, in degrees Fahrenheit?

A. 2
B. 4
C. 10
D. 14


Sagot :

To solve the problem, we need to determine the high temperature of the day given the low temperature and the difference between the high and low temperatures.

Let's break down the information provided:

1. The low temperature is [tex]\(-4^\circ F\)[/tex].
2. The difference between the high temperature [tex]\(h\)[/tex] and the low temperature is [tex]\(6^\circ\)[/tex].

We start with the equation given in the problem:

[tex]\[ h - (-4) - 6 = 0 \][/tex]

Solving this equation step-by-step:

1. Simplify the expression within the equation:
[tex]\[ h - (-4) \text{ is equivalent to } h + 4 \][/tex]

So, substituting [tex]\(h - (-4)\)[/tex] with [tex]\(h + 4\)[/tex], the equation becomes:
[tex]\[ h + 4 - 6 = 0 \][/tex]

2. Combine like terms:
[tex]\[ h + 4 - 6 = h - 2 \][/tex]

So the equation now is:
[tex]\[ h - 2 = 0 \][/tex]

3. Solve for [tex]\(h\)[/tex]:
[tex]\[ h - 2 = 0 \implies h = 2 \][/tex]

Therefore, the high temperature in the town that day was [tex]\(2^\circ F\)[/tex].

So, the correct answer is:
[tex]\[ \boxed{2} \][/tex]