Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine which point lies on the circle represented by the equation [tex]\(x^2 + (y - 12)^2 = 25^2\)[/tex], we need to check each point given in the options to see if it satisfies this equation.
The circle equation is:
[tex]\[x^2 + (y - 12)^2 = 625\][/tex]
since [tex]\(625\)[/tex] is [tex]\(25^2\)[/tex].
Let's check each point:
Point A: [tex]\((20, -3)\)[/tex]
Substitute [tex]\(x = 20\)[/tex] and [tex]\(y = -3\)[/tex] into the equation:
[tex]\[20^2 + (-3 - 12)^2 = 400 + (-15)^2 \][/tex]
[tex]\[ = 400 + 225 \][/tex]
[tex]\[ = 625\][/tex]
So, the left side equals the right side [tex]\(625\)[/tex]. Therefore, point A satisfies the equation.
Point B: [tex]\((-7, 24)\)[/tex]
Substitute [tex]\(x = -7\)[/tex] and [tex]\(y = 24\)[/tex] into the equation:
[tex]\((-7)^2 + (24 - 12)^2 = 49 + 12^2 \] \[ = 49 + 144 \] \[ = 193\] The left side does not equal the right side \(625\)[/tex]. Therefore, point B does not satisfy the equation.
Point C: [tex]\((0, 13)\)[/tex]
Substitute [tex]\(x = 0\)[/tex] and [tex]\(y = 13\)[/tex] into the equation:
[tex]\[0^2 + (13 - 12)^2 = 0 + 1^2 \][/tex]
[tex]\[ = 0 + 1 \][/tex]
[tex]\[ = 1\][/tex]
The left side does not equal the right side [tex]\(625\)[/tex]. Therefore, point C does not satisfy the equation.
Point D: [tex]\((-25, -13)\)[/tex]
Substitute [tex]\(x = -25\)[/tex] and [tex]\(y = -13\)[/tex] into the equation:
[tex]\((-25)^2 + (-13 - 12)^2 = 625 + (-25)^2 \] \[ = 625 + 625 \] \[ = 1250\] The left side does not equal the right side \(625\)[/tex]. Therefore, point D does not satisfy the equation.
From the calculations above, only point A [tex]\((20, -3)\)[/tex] satisfies the circle equation [tex]\(x^2 + (y - 12)^2 = 25^2\)[/tex].
Therefore, the point that lies on the circle is: [tex]\((20, -3)\)[/tex], and the answer is A.
The circle equation is:
[tex]\[x^2 + (y - 12)^2 = 625\][/tex]
since [tex]\(625\)[/tex] is [tex]\(25^2\)[/tex].
Let's check each point:
Point A: [tex]\((20, -3)\)[/tex]
Substitute [tex]\(x = 20\)[/tex] and [tex]\(y = -3\)[/tex] into the equation:
[tex]\[20^2 + (-3 - 12)^2 = 400 + (-15)^2 \][/tex]
[tex]\[ = 400 + 225 \][/tex]
[tex]\[ = 625\][/tex]
So, the left side equals the right side [tex]\(625\)[/tex]. Therefore, point A satisfies the equation.
Point B: [tex]\((-7, 24)\)[/tex]
Substitute [tex]\(x = -7\)[/tex] and [tex]\(y = 24\)[/tex] into the equation:
[tex]\((-7)^2 + (24 - 12)^2 = 49 + 12^2 \] \[ = 49 + 144 \] \[ = 193\] The left side does not equal the right side \(625\)[/tex]. Therefore, point B does not satisfy the equation.
Point C: [tex]\((0, 13)\)[/tex]
Substitute [tex]\(x = 0\)[/tex] and [tex]\(y = 13\)[/tex] into the equation:
[tex]\[0^2 + (13 - 12)^2 = 0 + 1^2 \][/tex]
[tex]\[ = 0 + 1 \][/tex]
[tex]\[ = 1\][/tex]
The left side does not equal the right side [tex]\(625\)[/tex]. Therefore, point C does not satisfy the equation.
Point D: [tex]\((-25, -13)\)[/tex]
Substitute [tex]\(x = -25\)[/tex] and [tex]\(y = -13\)[/tex] into the equation:
[tex]\((-25)^2 + (-13 - 12)^2 = 625 + (-25)^2 \] \[ = 625 + 625 \] \[ = 1250\] The left side does not equal the right side \(625\)[/tex]. Therefore, point D does not satisfy the equation.
From the calculations above, only point A [tex]\((20, -3)\)[/tex] satisfies the circle equation [tex]\(x^2 + (y - 12)^2 = 25^2\)[/tex].
Therefore, the point that lies on the circle is: [tex]\((20, -3)\)[/tex], and the answer is A.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.