Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To solve the problem of determining the formula unit for a compound made from [tex]\( Fe^{3+} \)[/tex] and oxygen, let’s follow these steps:
1. Identify the Charges:
- The iron (Fe) ion has a charge of +3, denoted as [tex]\( Fe^{3+} \)[/tex].
- The oxygen (O) ion typically has a charge of -2, denoted as [tex]\( O^{2-} \)[/tex].
2. Balance the Charges:
- To form a stable ionic compound, the total charge must be zero.
- We need to balance the positive charge from the iron ions with the negative charge from the oxygen ions.
3. Determine the Ratio of Ions:
- Since [tex]\( Fe^{3+} \)[/tex] has a +3 charge and [tex]\( O^{2-} \)[/tex] has a -2 charge, we need to find the smallest ratio of ions that results in a net charge of zero.
- We calculate the least common multiple (LCM) of the charges (3 and 2), which is 6. This means we need 6 positive charges to balance 6 negative charges.
4. Calculate the Number of Ions Needed:
- To get 6 positive charges, we need 2 [tex]\( Fe^{3+} \)[/tex] ions (because [tex]\( 2 \times 3 = 6 \)[/tex]).
- To get 6 negative charges, we need 3 [tex]\( O^{2-} \)[/tex] ions (because [tex]\( 3 \times -2 = -6 \)[/tex]).
5. Formula Unit:
- Combining these ions in the ratio needed to balance the charges, we get [tex]\( Fe_2O_3 \)[/tex].
So, the formula unit for a compound made from [tex]\( Fe^{3+} \)[/tex] and oxygen is:
[tex]\[ Fe_2O_3 \][/tex]
Matching Question:
- A nonmetal that gained two electrons is typically written as [tex]\( D^{2-} \)[/tex].
- Therefore, match: D [tex]$^{2-}$[/tex] - A) A nonmetal that gained two electrons
Summarizing:
- [tex]\( Fe_2O_3 \)[/tex] is the formula unit for the compound formed by [tex]\( Fe^{3+} \)[/tex] and oxygen.
Thus, for the multiple-choice question:
Correct Answer: [tex]\( Fe_2O_3 \)[/tex].
1. Identify the Charges:
- The iron (Fe) ion has a charge of +3, denoted as [tex]\( Fe^{3+} \)[/tex].
- The oxygen (O) ion typically has a charge of -2, denoted as [tex]\( O^{2-} \)[/tex].
2. Balance the Charges:
- To form a stable ionic compound, the total charge must be zero.
- We need to balance the positive charge from the iron ions with the negative charge from the oxygen ions.
3. Determine the Ratio of Ions:
- Since [tex]\( Fe^{3+} \)[/tex] has a +3 charge and [tex]\( O^{2-} \)[/tex] has a -2 charge, we need to find the smallest ratio of ions that results in a net charge of zero.
- We calculate the least common multiple (LCM) of the charges (3 and 2), which is 6. This means we need 6 positive charges to balance 6 negative charges.
4. Calculate the Number of Ions Needed:
- To get 6 positive charges, we need 2 [tex]\( Fe^{3+} \)[/tex] ions (because [tex]\( 2 \times 3 = 6 \)[/tex]).
- To get 6 negative charges, we need 3 [tex]\( O^{2-} \)[/tex] ions (because [tex]\( 3 \times -2 = -6 \)[/tex]).
5. Formula Unit:
- Combining these ions in the ratio needed to balance the charges, we get [tex]\( Fe_2O_3 \)[/tex].
So, the formula unit for a compound made from [tex]\( Fe^{3+} \)[/tex] and oxygen is:
[tex]\[ Fe_2O_3 \][/tex]
Matching Question:
- A nonmetal that gained two electrons is typically written as [tex]\( D^{2-} \)[/tex].
- Therefore, match: D [tex]$^{2-}$[/tex] - A) A nonmetal that gained two electrons
Summarizing:
- [tex]\( Fe_2O_3 \)[/tex] is the formula unit for the compound formed by [tex]\( Fe^{3+} \)[/tex] and oxygen.
Thus, for the multiple-choice question:
Correct Answer: [tex]\( Fe_2O_3 \)[/tex].
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.