At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To analyze the error Loren made, we need to determine the correct way to find the y-intercept [tex]\(b\)[/tex] in the equation of the trend line in the form [tex]\(y = mx + b\)[/tex].
Given:
- Two points: [tex]\((1, 130)\)[/tex] and [tex]\((10, 149)\)[/tex].
- Loren mistakenly used the equation [tex]\(10 = \frac{19}{9}(149) + b\)[/tex].
Let's follow Loren's mistaken approach and compare it with the correct approach.
1. Calculate the correct slope [tex]\( m \)[/tex]:
[tex]\[ m = \frac{149 - 130}{10 - 1} = \frac{19}{9} \][/tex]
2. Using the provided point ([tex]\(10, 149\)[/tex]), let’s find [tex]\( b \)[/tex]:
Using [tex]\(y = mx + b\)[/tex],
[tex]\[ 149 = \frac{19}{9}(10) + b \\ b = 149 - \frac{19}{9} \cdot 10 \][/tex]
So,
[tex]\[ b \approx 149 - 21.11 \approx 127.89 \][/tex]
3. Evaluate the provided options:
- First option: She should have solved [tex]\(10 = \frac{9}{19}(149) + b\)[/tex]
[tex]\[ b = 10 - \frac{9}{19} \cdot 149 \][/tex]
[tex]\[ b \approx 10 - 70.58 \approx -60.58 \][/tex]
This result does not fit our scenario and calculation.
- Second option: She should have solved [tex]\(1 = \frac{19}{9}(130) + b\)[/tex]
[tex]\[ b = 1 - \frac{19}{9} \cdot 130 \][/tex]
[tex]\[ b \approx 1 - 273.44 \approx -272.44 \][/tex]
This again is far from any logical solution for our scenario.
- Third option: She should have solved [tex]\(149 = \frac{19}{9}(10) + b\)[/tex]
[tex]\[ b = 149 - \frac{19}{9} \cdot 10 \][/tex]
[tex]\[ b \approx 149 - 21.11 \approx 127.89 \][/tex]
This matches our correct y-intercept calculation precisely.
- Fourth option: She should have solved [tex]\(130 = \frac{9}{19}(1) + b\)[/tex]
[tex]\[ b = 130 - \frac{9}{19} \cdot 1 \][/tex]
[tex]\[ b \approx 130 - 0.47 \approx 129.53 \][/tex]
This option deviates from our actual calculation.
Hence, after evaluating all the provided options, we find that the third option is correct. Loren should have solved:
[tex]\[ 149 = \frac{19}{9}(10) + b \][/tex]
Therefore, the error she made is that she should have solved [tex]\(149 = \frac{19}{9}(10) + b\)[/tex] for [tex]\(b\)[/tex].
Given:
- Two points: [tex]\((1, 130)\)[/tex] and [tex]\((10, 149)\)[/tex].
- Loren mistakenly used the equation [tex]\(10 = \frac{19}{9}(149) + b\)[/tex].
Let's follow Loren's mistaken approach and compare it with the correct approach.
1. Calculate the correct slope [tex]\( m \)[/tex]:
[tex]\[ m = \frac{149 - 130}{10 - 1} = \frac{19}{9} \][/tex]
2. Using the provided point ([tex]\(10, 149\)[/tex]), let’s find [tex]\( b \)[/tex]:
Using [tex]\(y = mx + b\)[/tex],
[tex]\[ 149 = \frac{19}{9}(10) + b \\ b = 149 - \frac{19}{9} \cdot 10 \][/tex]
So,
[tex]\[ b \approx 149 - 21.11 \approx 127.89 \][/tex]
3. Evaluate the provided options:
- First option: She should have solved [tex]\(10 = \frac{9}{19}(149) + b\)[/tex]
[tex]\[ b = 10 - \frac{9}{19} \cdot 149 \][/tex]
[tex]\[ b \approx 10 - 70.58 \approx -60.58 \][/tex]
This result does not fit our scenario and calculation.
- Second option: She should have solved [tex]\(1 = \frac{19}{9}(130) + b\)[/tex]
[tex]\[ b = 1 - \frac{19}{9} \cdot 130 \][/tex]
[tex]\[ b \approx 1 - 273.44 \approx -272.44 \][/tex]
This again is far from any logical solution for our scenario.
- Third option: She should have solved [tex]\(149 = \frac{19}{9}(10) + b\)[/tex]
[tex]\[ b = 149 - \frac{19}{9} \cdot 10 \][/tex]
[tex]\[ b \approx 149 - 21.11 \approx 127.89 \][/tex]
This matches our correct y-intercept calculation precisely.
- Fourth option: She should have solved [tex]\(130 = \frac{9}{19}(1) + b\)[/tex]
[tex]\[ b = 130 - \frac{9}{19} \cdot 1 \][/tex]
[tex]\[ b \approx 130 - 0.47 \approx 129.53 \][/tex]
This option deviates from our actual calculation.
Hence, after evaluating all the provided options, we find that the third option is correct. Loren should have solved:
[tex]\[ 149 = \frac{19}{9}(10) + b \][/tex]
Therefore, the error she made is that she should have solved [tex]\(149 = \frac{19}{9}(10) + b\)[/tex] for [tex]\(b\)[/tex].
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.