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Sagot :
Let's go through this step-by-step and determine the fractions for each phenotype.
### Step 1: Parent Genotypes
- Parent 1 genotypes: bbee (homozygous recessive for both traits)
- Parent 2 genotypes: BbEe (dihybrid)
### Step 2: Gametes
- Parent 1 can produce gametes: be
- Parent 2 can produce gametes: BE, Be, bE, be
### Step 3: Punnett Square
We create a Punnett square using the gametes from each parent. The gametes from Parent 1 will be along one axis (here, it produces only 'be'), and the gametes from Parent 2 will be along the other axis.
| | BE | Be | bE | be |
|-------|----|----|----|----|
| be| BbeE | Bbee | bbeE | bbee |
Let's list out each genotype and their corresponding phenotypes:
1. BbEe: Black Fur and Black Eyes
2. Bbee: Black Fur and Red Eyes
3. bbEe: White Fur and Black Eyes
4. bbee: White Fur and Red Eyes
### Step 4: Offspring Genotype and Phenotype
Considering that there are equal chances of forming each combination from the Punnett square, we can now determine the frequency of each phenotype:
1. BbEe: 4 out of 16 (Black Fur and Black Eyes)
2. Bbee: 4 out of 16 (Black Fur and Red Eyes)
3. bbEe: 4 out of 16 (White Fur and Black Eyes)
4. bbee: 4 out of 16 (White Fur and Red Eyes)
### Step 5: Predicted Fraction
We now summarize this information in a table:
[tex]\[ \begin{tabular}{||c||c|c|c|c|} \hline \hline & \begin{tabular}{c} Black \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} Black \\ Fur and \\ Red \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Red \\ Eyes \end{tabular} \\ \hline \begin{tabular}{c} Predicted \\ Fraction \end{tabular} & \frac{4}{16} & \frac{4}{16} & \frac{4}{16} & \frac{4}{16} \\ \hline \hline \end{tabular} \][/tex]
Simplified, each fraction becomes:
[tex]\[ \begin{tabular}{||c||c|c|c|c|} \hline \hline & \begin{tabular}{c} Black \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} Black \\ Fur and \\ Red \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Red \\ Eyes \end{tabular} \\ \hline \begin{tabular}{c} Predicted \\ Fraction \end{tabular} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\ \hline \hline \end{tabular} \][/tex]
Thus, the predicted fractions of each phenotype are:
- 1/4 for Black Fur and Black Eyes
- 1/4 for Black Fur and Red Eyes
- 1/4 for White Fur and Black Eyes
- 1/4 for White Fur and Red Eyes
### Step 1: Parent Genotypes
- Parent 1 genotypes: bbee (homozygous recessive for both traits)
- Parent 2 genotypes: BbEe (dihybrid)
### Step 2: Gametes
- Parent 1 can produce gametes: be
- Parent 2 can produce gametes: BE, Be, bE, be
### Step 3: Punnett Square
We create a Punnett square using the gametes from each parent. The gametes from Parent 1 will be along one axis (here, it produces only 'be'), and the gametes from Parent 2 will be along the other axis.
| | BE | Be | bE | be |
|-------|----|----|----|----|
| be| BbeE | Bbee | bbeE | bbee |
Let's list out each genotype and their corresponding phenotypes:
1. BbEe: Black Fur and Black Eyes
2. Bbee: Black Fur and Red Eyes
3. bbEe: White Fur and Black Eyes
4. bbee: White Fur and Red Eyes
### Step 4: Offspring Genotype and Phenotype
Considering that there are equal chances of forming each combination from the Punnett square, we can now determine the frequency of each phenotype:
1. BbEe: 4 out of 16 (Black Fur and Black Eyes)
2. Bbee: 4 out of 16 (Black Fur and Red Eyes)
3. bbEe: 4 out of 16 (White Fur and Black Eyes)
4. bbee: 4 out of 16 (White Fur and Red Eyes)
### Step 5: Predicted Fraction
We now summarize this information in a table:
[tex]\[ \begin{tabular}{||c||c|c|c|c|} \hline \hline & \begin{tabular}{c} Black \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} Black \\ Fur and \\ Red \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Red \\ Eyes \end{tabular} \\ \hline \begin{tabular}{c} Predicted \\ Fraction \end{tabular} & \frac{4}{16} & \frac{4}{16} & \frac{4}{16} & \frac{4}{16} \\ \hline \hline \end{tabular} \][/tex]
Simplified, each fraction becomes:
[tex]\[ \begin{tabular}{||c||c|c|c|c|} \hline \hline & \begin{tabular}{c} Black \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} Black \\ Fur and \\ Red \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Black \\ Eyes \end{tabular} & \begin{tabular}{c} White \\ Fur and \\ Red \\ Eyes \end{tabular} \\ \hline \begin{tabular}{c} Predicted \\ Fraction \end{tabular} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} & \frac{1}{4} \\ \hline \hline \end{tabular} \][/tex]
Thus, the predicted fractions of each phenotype are:
- 1/4 for Black Fur and Black Eyes
- 1/4 for Black Fur and Red Eyes
- 1/4 for White Fur and Black Eyes
- 1/4 for White Fur and Red Eyes
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