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Sagot :
To determine the percentage of students eating outside during the first and second lunch periods, we need to calculate the relevant percentages using the given data.
### Step-by-Step Solution:
1. Calculate the percentage for first lunch:
- Number of students who eat outside = 0.19
- Total number of students during first lunch = 0.54
The percentage of students eating outside during first lunch is:
[tex]\[ \text{Percentage}_{\text{First Lunch}} = \left( \frac{0.19}{0.54} \right) \times 100 \][/tex]
2. Calculate the percentage:
[tex]\[ \text{Percentage}_{\text{First Lunch}} = \left( \frac{0.19}{0.54} \right) \times 100 \approx 35.19\% \][/tex]
3. Calculate the percentage for second lunch:
- Number of students who eat outside = 0.18
- Total number of students during second lunch = 0.46
The percentage of students eating outside during second lunch is:
[tex]\[ \text{Percentage}_{\text{Second Lunch}} = \left( \frac{0.18}{0.46} \right) \times 100 \][/tex]
4. Calculate the percentage:
[tex]\[ \text{Percentage}_{\text{Second Lunch}} = \left( \frac{0.18}{0.46} \right) \times 100 \approx 39.13\% \][/tex]
### Conclusion:
- The percentage of second-lunch students who eat outside is approximately [tex]\(39.13\%\)[/tex].
Therefore, the true statement is:
A. A greater percentage of second-lunch students ([tex]$39 \%$[/tex]) eat outside.
### Step-by-Step Solution:
1. Calculate the percentage for first lunch:
- Number of students who eat outside = 0.19
- Total number of students during first lunch = 0.54
The percentage of students eating outside during first lunch is:
[tex]\[ \text{Percentage}_{\text{First Lunch}} = \left( \frac{0.19}{0.54} \right) \times 100 \][/tex]
2. Calculate the percentage:
[tex]\[ \text{Percentage}_{\text{First Lunch}} = \left( \frac{0.19}{0.54} \right) \times 100 \approx 35.19\% \][/tex]
3. Calculate the percentage for second lunch:
- Number of students who eat outside = 0.18
- Total number of students during second lunch = 0.46
The percentage of students eating outside during second lunch is:
[tex]\[ \text{Percentage}_{\text{Second Lunch}} = \left( \frac{0.18}{0.46} \right) \times 100 \][/tex]
4. Calculate the percentage:
[tex]\[ \text{Percentage}_{\text{Second Lunch}} = \left( \frac{0.18}{0.46} \right) \times 100 \approx 39.13\% \][/tex]
### Conclusion:
- The percentage of second-lunch students who eat outside is approximately [tex]\(39.13\%\)[/tex].
Therefore, the true statement is:
A. A greater percentage of second-lunch students ([tex]$39 \%$[/tex]) eat outside.
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