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Solve [tex]\frac{2t + 5}{3} \ \textless \ -9[/tex] for [tex]t[/tex].

A. [tex]t \ \textless \ -16[/tex]
B. [tex]t \ \textgreater \ -11[/tex]
C. [tex]t \ \textgreater \ -16[/tex]
D. [tex]t \ \textless \ -11[/tex]

Sagot :

To solve the inequality [tex]\(\frac{2t + 5}{3} < -9\)[/tex] for [tex]\(t\)[/tex], follow these steps:

1. Remove the fraction: To eliminate the fraction, multiply both sides of the inequality by 3:
[tex]\[ 3 \cdot \frac{2t + 5}{3} < 3 \cdot (-9) \][/tex]
Simplifying this, we get:
[tex]\[ 2t + 5 < -27 \][/tex]

2. Isolate the term with [tex]\(t\)[/tex]: Subtract 5 from both sides of the inequality to isolate the term that contains [tex]\(t\)[/tex]:
[tex]\[ 2t + 5 - 5 < -27 - 5 \][/tex]
Simplifying this, we get:
[tex]\[ 2t < -32 \][/tex]

3. Solve for [tex]\(t\)[/tex]: Finally, divide both sides of the inequality by 2 to solve for [tex]\(t\)[/tex]:
[tex]\[ \frac{2t}{2} < \frac{-32}{2} \][/tex]
Simplifying this, we get:
[tex]\[ t < -16 \][/tex]

Therefore, the solution to the inequality [tex]\(\frac{2t + 5}{3} < -9\)[/tex] is:
[tex]\[ t < -16 \][/tex]