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A monkey running at [tex]$1.24 \, \text{m/s}$[/tex] accelerates to travel [tex]6.71 \, \text{m}$[/tex] in [tex]4.55 \, \text{s}$[/tex]. What is the final velocity of the monkey?

[tex]v_f = \, ? \, \text{m/s}[/tex]


Sagot :

Sure! To determine the final velocity of the monkey, we need to follow a step-by-step approach using physics principles, specifically kinematic equations.

### Step-by-Step Solution:

1. Identify the given values:
- Initial velocity ([tex]\(u\)[/tex]): 1.24 m/s
- Distance traveled ([tex]\(s\)[/tex]): 6.71 meters
- Time taken ([tex]\(t\)[/tex]): 4.55 seconds

2. Use the kinematic equation to find the acceleration ([tex]\(a\)[/tex]):
The equation relating distance, initial velocity, acceleration, and time is:
[tex]\[ s = ut + \frac{1}{2} a t^2 \][/tex]

Substitute the known values into the equation:
[tex]\[ 6.71 = (1.24 \cdot 4.55) + \frac{1}{2} a (4.55)^2 \][/tex]

3. Calculate the initial velocity component:
[tex]\[ (1.24 \times 4.55) = 5.642 \][/tex]

4. Isolate the term involving acceleration:
[tex]\[ 6.71 - 5.642 = \frac{1}{2} a (4.55)^2 \][/tex]
[tex]\[ 1.068 = \frac{1}{2} a (20.7025) \][/tex]

5. Solve for acceleration ([tex]\(a\)[/tex]):
[tex]\[ 1.068 = 10.35125a \][/tex]
[tex]\[ a = \frac{1.068}{10.35125} = 0.103 \][/tex]

6. Use the final velocity equation to find the final velocity ([tex]\(v_f\)[/tex]):
The equation relating final velocity, initial velocity, acceleration, and time is:
[tex]\[ v_f = u + a t \][/tex]

Substitute the known values:
[tex]\[ v_f = 1.24 + (0.103 \times 4.55) \][/tex]

7. Calculate the final velocity:
[tex]\[ v_f = 1.24 + 0.469 \][/tex]
[tex]\[ v_f = 1.709 \][/tex]

Therefore, the final velocity of the monkey is [tex]\(1.709 \, \text{m/s}\)[/tex].