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Solve the inequality: [tex]4x + 6 \leq 18[/tex]

A. [tex]x \leq 3[/tex]
B. [tex]x \leq 6[/tex]
C. [tex]x \leq 48[/tex]
D. [tex]x \leq 96[/tex]


Sagot :

To solve the inequality [tex]\(4x + 6 \leq 18\)[/tex], follow these detailed steps:

1. Start with the given inequality:
[tex]\[ 4x + 6 \leq 18 \][/tex]

2. Isolate the term involving [tex]\(x\)[/tex]:
- Subtract 6 from both sides of the inequality to get rid of the constant term on the left side.
[tex]\[ 4x + 6 - 6 \leq 18 - 6 \][/tex]
Simplifying this, we have:
[tex]\[ 4x \leq 12 \][/tex]

3. Solve for [tex]\(x\)[/tex]:
- Divide both sides of the inequality by 4 (the coefficient of [tex]\(x\)[/tex]) to isolate [tex]\(x\)[/tex].
[tex]\[ \frac{4x}{4} \leq \frac{12}{4} \][/tex]
Simplifying this, we get:
[tex]\[ x \leq 3 \][/tex]

Thus, the solution to the inequality [tex]\(4x + 6 \leq 18\)[/tex] is:
[tex]\[ x \leq 3 \][/tex]
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