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For what value of [tex]$x$[/tex] is [tex]$\sin (x) = \cos \left(32^{\circ}\right)$[/tex], where [tex][tex]$0^{\circ} \ \textless \ x \ \textless \ 90^{\circ}$[/tex][/tex]?

A. [tex]$32^{\circ}$[/tex]
B. [tex]$13^{\circ}$[/tex]
C. [tex][tex]$58^{\circ}$[/tex][/tex]
D. [tex]$64^{\circ}$[/tex]

Sagot :

To determine the value of [tex]\(x\)[/tex] for which [tex]\(\sin(x) = \cos(32^\circ)\)[/tex] within the range [tex]\(0^\circ < x < 90^\circ\)[/tex], we can use a fundamental trigonometric identity that relates sine and cosine.

Recall the cofunction identity, which states that:

[tex]\[ \sin(x) = \cos(90^\circ - x) \][/tex]

This identity tells us that the sine of an angle is equal to the cosine of its complement. Here, we need [tex]\(\sin(x)\)[/tex] to equal [tex]\(\cos(32^\circ)\)[/tex]. Using the cofunction identity, we can express this as:

[tex]\[ \sin(x) = \cos(32^\circ) = \cos(90^\circ - y) \][/tex]

For some angle [tex]\(y\)[/tex]. From the identity, we see that the cosine of an angle is equal to the sine of its complement. Therefore, we can set:

[tex]\[ 32^\circ = 90^\circ - x \][/tex]

To solve for [tex]\(x\)[/tex], isolate [tex]\(x\)[/tex] on one side of the equation:

[tex]\[ x = 90^\circ - 32^\circ \][/tex]

Subtract the values:

[tex]\[ x = 58^\circ \][/tex]

Thus, the value of [tex]\(x\)[/tex] for which [tex]\(\sin(x) = \cos(32^\circ)\)[/tex] in the specified range is:

[tex]\[ \boxed{58^\circ} \][/tex]