Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Which of the following equations is represented by a graph that is centered at [tex]$(-6,-8)$[/tex] and includes the point [tex]$(0,-8)$[/tex]?

A. [tex]$(x-6)^2+(y-8)^2=6$[/tex]
B. [tex]$(x-6)^2+(y-8)^2=36$[/tex]
C. [tex]$(x+6)^2+(y+8)^2=6$[/tex]
D. [tex]$(x+6)^2+(y+8)^2=36$[/tex]


Sagot :

Sure! Let's solve this step by step.

The general equation for a circle in the coordinate plane with the center [tex]\((h, k)\)[/tex] and radius [tex]\(r\)[/tex] is given by:

[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]

Here, the center of the circle is given as [tex]\((-6, -8)\)[/tex]. Substituting [tex]\(h = -6\)[/tex] and [tex]\(k = -8\)[/tex] into the general equation, we get:

[tex]\[ (x + 6)^2 + (y + 8)^2 = r^2 \][/tex]

Next, we need to determine the radius [tex]\(r\)[/tex]. To do this, we use the point [tex]\((0, -8)\)[/tex], which lies on the circle.

Substitute [tex]\(x = 0\)[/tex] and [tex]\(y = -8\)[/tex] into the equation:

[tex]\[ (0 + 6)^2 + (-8 + 8)^2 = r^2 \][/tex]

This simplifies to:

[tex]\[ 6^2 + 0^2 = r^2 \][/tex]

[tex]\[ 36 + 0 = r^2 \][/tex]

[tex]\[ r^2 = 36 \][/tex]

So, the equation of the circle is:

[tex]\[ (x + 6)^2 + (y + 8)^2 = 36 \][/tex]

Among the given options, we must find the equation that matches this form. The options are:

1. [tex]\((x-6)^2 + (y-8)^2 = 6\)[/tex]
2. [tex]\((x-6)^2 + (y-8)^2 = 36\)[/tex]
3. [tex]\((x+6)^2 + (y+8)^2 = 6\)[/tex]
4. [tex]\((x+6)^2 + (y+8)^2 = 36\)[/tex]

The correct option is:

[tex]\[ (x + 6)^2 + (y + 8)^2 = 36 \][/tex]

Therefore, the correct answer is the fourth option:

[tex]\[ (x+6)^2 + (y+8)^2 = 36 \][/tex]