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You are riding a bicycle. If you apply a forward force of 125 N, and the bicycle and you have a combined mass of 82 kg, what will be the forward acceleration of the bicycle? (Assume there is no friction.)

A. [tex]$0.66 \, \text{m/s}^2$[/tex]
B. [tex]$1.52 \, \text{m/s}^2$[/tex]
C. [tex][tex]$1.67 \, \text{m/s}^2$[/tex][/tex]
D. [tex]$3.37 \, \text{m/s}^2$[/tex]

Sagot :

To determine the forward acceleration of the bicycle when a force is applied, we use Newton's second law of motion. Newton's second law states that the acceleration [tex]\( a \)[/tex] of an object is directly proportional to the net force [tex]\( F \)[/tex] acting on it and inversely proportional to its mass [tex]\( m \)[/tex]. This relationship can be expressed with the formula:

[tex]\[ a = \frac{F}{m} \][/tex]

Given:
- The force applied [tex]\( F \)[/tex] is 125 Newtons (N)
- The combined mass of you and the bicycle [tex]\( m \)[/tex] is 82 kilograms (kg)

We need to find the acceleration [tex]\( a \)[/tex]. Plugging the given values into the formula:

[tex]\[ a = \frac{125 \, \text{N}}{82 \, \text{kg}} \][/tex]

Upon performing the division:

[tex]\[ a = \frac{125}{82} \approx 1.524390243902439 \][/tex]

Rounding the value to two decimal places, we get:

[tex]\[ a = 1.52 \, \text{m/s}^2 \][/tex]

So, the forward acceleration of the bicycle is approximately [tex]\( 1.52 \, \text{m/s}^2 \)[/tex].

From the given options, the correct answer is:
[tex]\[ \boxed{1.52 \, \text{m/s}^2} \][/tex]
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