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Use the information in the chart to answer the following question.

\begin{tabular}{|l|c|l|}
\hline
Element & Atomic Number & Charge \\
\hline
Lithium & 3 & [tex]$1+$[/tex] \\
\hline
Oxide & 8 & [tex]$2-$[/tex] \\
\hline
Magnesium & 12 & [tex]$2+$[/tex] \\
\hline
Aluminum & 13 & [tex]$3+$[/tex] \\
\hline
Chloride & 17 & [tex]$1-$[/tex] \\
\hline
Iron(III) & 26 & [tex]$3+$[/tex] \\
\hline
Nickel(II) & 28 & [tex]$2+$[/tex] \\
\hline
Iodide & 53 & [tex]$1-$[/tex] \\
\hline
\end{tabular}

The ion lithium achieves stability by

A. losing three electrons

B. losing one electron

C. gaining one electron

D. losing two electrons

Sagot :

To determine how lithium achieves stability, let's examine its electronic configuration and its behavior in forming ions.

1. Understanding Lithium's Atomic Number:
- Lithium (Li) has an atomic number of 3, which means it has 3 protons and, in its neutral state, 3 electrons.

2. Electron Configuration:
- The electron configuration of a neutral lithium atom is [tex]\(1s^2 2s^1\)[/tex]. This means:
- Two electrons are in the first energy level (1s).
- One electron is in the second, outermost energy level (2s).

3. Stability and Valence Electrons:
- Atoms achieve stability by having a full outer electron shell. For most elements, a complete outer shell consists of 8 electrons, but for small atoms like lithium, full stability can resemble the electron configuration of the nearest noble gas, Helium (He), which has 2 electrons.
- Lithium can achieve stability by modifying its electron configuration to match that of Helium.

4. Achieving Stability:
- To achieve this stability, lithium needs to lose its one electron in the outermost 2s shell. This results in the formation of a [tex]\(Li^+\)[/tex] ion, which then has 2 electrons (the same electron configuration as Helium).

Thus, lithium achieves stability by losing one electron. So, the correct answer is:

Losing one electron
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