atticus30
Answered

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Use the periodic table to answer the following question:

How many moles of [tex]$AgNO_3$[/tex] are present in 1.50 L of a 0.050 M solution?

[tex]\[\square\][/tex]

Sagot :

GinnyAnswer
Sure, let's solve the problem step-by-step:

1. Understand the Given Information:
- We have a solution with a volume of 1.50 liters (L).
- The molarity (concentration) of the solution is 0.050 moles per liter (M).

2. Recall the Formula for Moles:
The formula to find the number of moles ([tex]\(n\)[/tex]) from molarity (M) and volume (V) is:
[tex]\[ \text{moles} = \text{molarity} \times \text{volume} \][/tex]

3. Substitute the Given Values:
- Molarity ([tex]\(M\)[/tex]) = 0.050 M
- Volume ([tex]\(V\)[/tex]) = 1.50 L

4. Perform the Multiplication:
[tex]\[ \text{moles} = 0.050 \, \text{M} \times 1.50 \, \text{L} \][/tex]

5. Calculate the Result:
[tex]\[ \text{moles} = 0.075 \][/tex]

Therefore, the number of moles of [tex]\(AgNO_3\)[/tex] present in 1.50 liters of a 0.050 M solution is [tex]\(0.075\)[/tex].
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