Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To solve for [tex]\(\log_{0.5} 16\)[/tex], we need to determine the exponent [tex]\(x\)[/tex] such that [tex]\(0.5^x = 16\)[/tex].
Let's go through the steps to solve for [tex]\(x\)[/tex]:
1. Understand the base and the number: We are given the base [tex]\(0.5\)[/tex] and the number [tex]\(16\)[/tex].
2. Express the logarithmic equation in exponential form: The equation [tex]\(\log_{0.5} 16 = x\)[/tex] can be rewritten as:
[tex]\[ 0.5^x = 16 \][/tex]
3. Rewrite 0.5 as a power of 2: Since [tex]\(0.5\)[/tex] is equal to [tex]\(\frac{1}{2}\)[/tex], we can rewrite the equation with base [tex]\(2\)[/tex]:
[tex]\[ \left(\frac{1}{2}\right)^x = 16 \][/tex]
4. Simplify the base [tex]\(\frac{1}{2}\)[/tex]: The term [tex]\(\frac{1}{2}\)[/tex] can be rewritten as [tex]\(2^{-1}\)[/tex]:
[tex]\[ (2^{-1})^x = 16 \][/tex]
5. Apply the power rule of exponents: When raising a power to another power, multiply the exponents:
[tex]\[ 2^{-x} = 16 \][/tex]
6. Rewrite 16 as a power of 2: We know that [tex]\(16 = 2^4\)[/tex], so the equation becomes:
[tex]\[ 2^{-x} = 2^4 \][/tex]
7. Set the exponents equal to each other: Since the bases are the same, we can set the exponents equal:
[tex]\[ -x = 4 \][/tex]
8. Solve for [tex]\(x\)[/tex]: We isolate [tex]\(x\)[/tex] by dividing both sides by [tex]\(-1\)[/tex]:
[tex]\[ x = -4 \][/tex]
Thus, the value of [tex]\(\log_{0.5} 16\)[/tex] is [tex]\(-4.0\)[/tex].
Therefore, the correct answer is [tex]\(-4.00\)[/tex].
Let's go through the steps to solve for [tex]\(x\)[/tex]:
1. Understand the base and the number: We are given the base [tex]\(0.5\)[/tex] and the number [tex]\(16\)[/tex].
2. Express the logarithmic equation in exponential form: The equation [tex]\(\log_{0.5} 16 = x\)[/tex] can be rewritten as:
[tex]\[ 0.5^x = 16 \][/tex]
3. Rewrite 0.5 as a power of 2: Since [tex]\(0.5\)[/tex] is equal to [tex]\(\frac{1}{2}\)[/tex], we can rewrite the equation with base [tex]\(2\)[/tex]:
[tex]\[ \left(\frac{1}{2}\right)^x = 16 \][/tex]
4. Simplify the base [tex]\(\frac{1}{2}\)[/tex]: The term [tex]\(\frac{1}{2}\)[/tex] can be rewritten as [tex]\(2^{-1}\)[/tex]:
[tex]\[ (2^{-1})^x = 16 \][/tex]
5. Apply the power rule of exponents: When raising a power to another power, multiply the exponents:
[tex]\[ 2^{-x} = 16 \][/tex]
6. Rewrite 16 as a power of 2: We know that [tex]\(16 = 2^4\)[/tex], so the equation becomes:
[tex]\[ 2^{-x} = 2^4 \][/tex]
7. Set the exponents equal to each other: Since the bases are the same, we can set the exponents equal:
[tex]\[ -x = 4 \][/tex]
8. Solve for [tex]\(x\)[/tex]: We isolate [tex]\(x\)[/tex] by dividing both sides by [tex]\(-1\)[/tex]:
[tex]\[ x = -4 \][/tex]
Thus, the value of [tex]\(\log_{0.5} 16\)[/tex] is [tex]\(-4.0\)[/tex].
Therefore, the correct answer is [tex]\(-4.00\)[/tex].
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.