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Select the correct answer.

Consider event [tex]$A$[/tex] and event [tex]$B$[/tex]. What is the probability that event [tex]$B$[/tex] occurs, given that event [tex]$A$[/tex] has occurred?

A. [tex]$\frac{P(B \cap A)}{P(A) \cdot P(B)}$[/tex]
B. [tex]$\frac{P(B \cap A)}{P(A)}$[/tex]
C. [tex]$\frac{P(B \cap A)}{P(B)}$[/tex]
D. [tex]$\frac{P(B \cup A)}{P(B)}$[/tex]


Sagot :

To determine the correct answer, let's recall the definition of conditional probability. Conditional probability allows us to find the probability of event [tex]\( B \)[/tex] occurring given that event [tex]\( A \)[/tex] has already occurred. This is denoted as [tex]\( P(B|A) \)[/tex].

According to the formula for conditional probability, we have:
[tex]\[ P(B|A) = \frac{P(B \cap A)}{P(A)} \][/tex]

This formula can be broken down as follows:
- [tex]\( P(B \cap A) \)[/tex] is the probability that both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occur.
- [tex]\( P(A) \)[/tex] is the probability that event [tex]\( A \)[/tex] occurs.
- [tex]\( P(B|A) \)[/tex] is the probability that event [tex]\( B \)[/tex] occurs given that event [tex]\( A \)[/tex] has occurred.

From the options provided:
A. [tex]\( \frac{ P(B \cap A)}{ P(A) \cdot P(B)} \)[/tex]
B. [tex]\( \frac{P(B \cap A)}{P(A)} \)[/tex]
C. [tex]\( \frac{ P(B \cap A)}{P(B)} \)[/tex]
D. [tex]\( \frac{ P(B \cup A)}{ P(B)} \)[/tex]

Based on the definition and formula for conditional probability, the correct answer is:
[tex]\[ B. \frac{P(B \cap A)}{P(A)} \][/tex]

Hence, the correct answer is:

[tex]\( \boxed{B} \)[/tex]
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