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What is the explicit rule for the geometric sequence?

[tex]\[4.05, 1.35, 0.45, 0.15, \ldots\][/tex]

A. [tex]\[a_n = 4.05 \left(\frac{1}{3}\right)^{n+1}\][/tex]

B. [tex]\[a_n = 4.05 \left(\frac{1}{3}\right)^{n+2}\][/tex]

C. [tex]\[a_n = 4.05 \left(\frac{1}{3}\right)^n\][/tex]

D. [tex]\[a_n = 4.05 \left(\frac{1}{3}\right)^{n-1}\][/tex]

Sagot :

To determine the explicit rule for a geometric sequence, we need to use the general form of the nth term of a geometric sequence, which is given by [tex]\( a_n = a \cdot r^{n-1} \)[/tex], where:
- [tex]\( a \)[/tex] is the first term of the sequence
- [tex]\( r \)[/tex] is the common ratio
- [tex]\( n \)[/tex] is the term number

Given the first few terms of the sequence are [tex]\( 4.05, 1.35, 0.45, 0.15, \ldots \)[/tex]:

1. Identifying the First Term:
The first term [tex]\( a \)[/tex] is clearly [tex]\( 4.05 \)[/tex].

2. Determining the Common Ratio:
To find the common ratio [tex]\( r \)[/tex], divide the second term by the first term:
[tex]\[ r = \frac{1.35}{4.05} \][/tex]
Simplifying this:
[tex]\[ r = \frac{1}{3} \approx 0.3333 \][/tex]

3. Finding the Explicit Rule:
Now, substitute [tex]\( a = 4.05 \)[/tex] and [tex]\( r = \frac{1}{3} \)[/tex] into the geometric sequence formula [tex]\( a_n = a \cdot r^{n-1} \)[/tex]:
[tex]\[ a_n = 4.05 \cdot \left(\frac{1}{3}\right)^{n-1} \][/tex]

Therefore, the explicit rule for the geometric sequence is:
[tex]\[ a_n = 4.05 \left( \frac{1}{3} \right)^{n-1} \][/tex]

Thus, the correct option is:
[tex]\[ a_n = 4.05 \left( \frac{1}{3} \right)^{n-1} \][/tex]