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Sagot :
To establish a recursive rule for the geometric sequence where the terms are [tex]\( 6, -24, 96, -384, \ldots \)[/tex]:
1. Identify the first term [tex]\( a_1 \)[/tex]:
[tex]\[ a_1 = 6 \][/tex]
2. Determine the common ratio [tex]\( r \)[/tex]:
The common ratio can be found by dividing the second term by the first term:
[tex]\[ r = \frac{-24}{6} = -4 \][/tex]
3. Write the recursive formula:
A geometric sequence can be defined recursively using the formula:
[tex]\[ a_n = a_{n-1} \times r \][/tex]
Here, [tex]\( a_{n-1} \)[/tex] represents the previous term, and [tex]\( r \)[/tex] is the common ratio.
Putting this information together, the recursive rule for the given geometric sequence is:
[tex]\[ a_1 = 6 \][/tex]
[tex]\[ a_n = a_{n-1} \times -4 \][/tex]
1. Identify the first term [tex]\( a_1 \)[/tex]:
[tex]\[ a_1 = 6 \][/tex]
2. Determine the common ratio [tex]\( r \)[/tex]:
The common ratio can be found by dividing the second term by the first term:
[tex]\[ r = \frac{-24}{6} = -4 \][/tex]
3. Write the recursive formula:
A geometric sequence can be defined recursively using the formula:
[tex]\[ a_n = a_{n-1} \times r \][/tex]
Here, [tex]\( a_{n-1} \)[/tex] represents the previous term, and [tex]\( r \)[/tex] is the common ratio.
Putting this information together, the recursive rule for the given geometric sequence is:
[tex]\[ a_1 = 6 \][/tex]
[tex]\[ a_n = a_{n-1} \times -4 \][/tex]
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