Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To find the value of [tex]\(\sec \theta\)[/tex], given that [tex]\(\tan^2 \theta = \frac{3}{8}\)[/tex], let's follow a step-by-step solution:
1. Identify the given information:
[tex]\(\tan^2 \theta = \frac{3}{8}\)[/tex]
2. Calculate [tex]\(\tan \theta\)[/tex]:
[tex]\[\tan \theta = \sqrt{\tan^2 \theta} = \sqrt{\frac{3}{8}}\][/tex]
3. Use the trigonometric identity involving sec and tan:
Recall that the identity [tex]\(\sec^2 \theta = 1 + \tan^2 \theta\)[/tex] relates secant and tangent.
4. Substitute [tex]\(\tan^2 \theta\)[/tex] into the identity:
[tex]\[\sec^2 \theta = 1 + \frac{3}{8}\][/tex]
5. Simplify the expression:
[tex]\[1 + \frac{3}{8} = \frac{8}{8} + \frac{3}{8} = \frac{11}{8}\][/tex]
Thus, we find:
[tex]\[\sec^2 \theta = \frac{11}{8}\][/tex]
6. Solve for [tex]\(\sec \theta\)[/tex]:
[tex]\[\sec \theta = \pm \sqrt{\sec^2 \theta} = \pm \sqrt{\frac{11}{8}}\][/tex]
Therefore, the value of [tex]\(\sec \theta\)[/tex] is [tex]\(\pm \sqrt{\frac{11}{8}}\)[/tex].
So, the correct answer is:
[tex]\(\pm \sqrt{\frac{11}{8}}\)[/tex]
1. Identify the given information:
[tex]\(\tan^2 \theta = \frac{3}{8}\)[/tex]
2. Calculate [tex]\(\tan \theta\)[/tex]:
[tex]\[\tan \theta = \sqrt{\tan^2 \theta} = \sqrt{\frac{3}{8}}\][/tex]
3. Use the trigonometric identity involving sec and tan:
Recall that the identity [tex]\(\sec^2 \theta = 1 + \tan^2 \theta\)[/tex] relates secant and tangent.
4. Substitute [tex]\(\tan^2 \theta\)[/tex] into the identity:
[tex]\[\sec^2 \theta = 1 + \frac{3}{8}\][/tex]
5. Simplify the expression:
[tex]\[1 + \frac{3}{8} = \frac{8}{8} + \frac{3}{8} = \frac{11}{8}\][/tex]
Thus, we find:
[tex]\[\sec^2 \theta = \frac{11}{8}\][/tex]
6. Solve for [tex]\(\sec \theta\)[/tex]:
[tex]\[\sec \theta = \pm \sqrt{\sec^2 \theta} = \pm \sqrt{\frac{11}{8}}\][/tex]
Therefore, the value of [tex]\(\sec \theta\)[/tex] is [tex]\(\pm \sqrt{\frac{11}{8}}\)[/tex].
So, the correct answer is:
[tex]\(\pm \sqrt{\frac{11}{8}}\)[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.