Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Which circuits correctly show Ohm's law?

A. [tex]25V, 5A, 5\Omega[/tex]

B. [tex]56V, 7A, 8\Omega[/tex]

C. [tex]18V, 6A, 3\Omega[/tex]

D. [tex]20V, 5A, 4\Omega[/tex]

Sagot :

GinnyAnswer
To determine which circuits correctly show Ohm's Law, we need to ensure that for each circuit, the voltage [tex]\( V \)[/tex], current [tex]\( I \)[/tex], and resistance [tex]\( R \)[/tex] satisfy the equation [tex]\( V = I \times R \)[/tex].

We are given the following data:

1. Circuit 1:
- [tex]\( V = 25 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps
- [tex]\( R = \text{unknown} \)[/tex]

2. Circuit 2:
- [tex]\( V = 56 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps
- [tex]\( R = 5 \)[/tex] ohms

3. Circuit 3:
- [tex]\( V = 18 \)[/tex] volts
- [tex]\( I = 7 \)[/tex] amps
- [tex]\( R = \text{unknown} \)[/tex]

4. Circuit 4:
- [tex]\( V = 20 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps
- [tex]\( R = \text{unknown} \)[/tex]

Let's go through each circuit step-by-step.

### Circuit 1:
- Given:
- [tex]\( V = 25 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps

- Calculate [tex]\( R \)[/tex]:
- [tex]\( R = \frac{V}{I} = \frac{25}{5} = 5 \)[/tex] ohms

Since [tex]\( V = I \times R \)[/tex] holds true with [tex]\( R = 5 \)[/tex] ohms, Circuit 1 correctly shows Ohm's law.

### Circuit 2:
- Given:
- [tex]\( V = 56 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps
- [tex]\( R = 5 \)[/tex] ohms

- Verify [tex]\( V = I \times R \)[/tex]:
- Check [tex]\( 56 = 5 \times 5 \)[/tex]

Since [tex]\( 56 \neq 25 \)[/tex], Circuit 2 does not correctly show Ohm's law.

### Circuit 3:
- Given:
- [tex]\( V = 18 \)[/tex] volts
- [tex]\( I = 7 \)[/tex] amps

- Calculate [tex]\( R \)[/tex]:
- [tex]\( R = \frac{V}{I} = \frac{18}{7} \approx 2.57 \)[/tex] ohms (not an integer)

Since [tex]\( R \)[/tex] is not an integer, Circuit 3 does not correctly show Ohm's law.

### Circuit 4:
- Given:
- [tex]\( V = 20 \)[/tex] volts
- [tex]\( I = 5 \)[/tex] amps

- Calculate [tex]\( R \)[/tex]:
- [tex]\( R = \frac{V}{I} = \frac{20}{5} = 4 \)[/tex] ohms

Since [tex]\( V = I \times R \)[/tex] holds true with [tex]\( R = 4 \)[/tex] ohms, Circuit 4 correctly shows Ohm's law.

### Summary:
Based on the analysis, Circuits 1 and 4 correctly show Ohm's law. Hence, the circuits that correctly demonstrate Ohm's law are:

[tex]\[ \text{Circuits 1 and 4} \][/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.