Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Consider circle [tex]\( T \)[/tex] with radius 24 in. and [tex]\(\theta=\frac{5 \pi}{6}\)[/tex] radians.

What is the length of minor arc [tex]\( SV \)[/tex]?

A. [tex]\(20 \pi\)[/tex] in.
B. [tex]\(28 \pi\)[/tex] in.
C. [tex]\(40 \pi\)[/tex] in.
D. [tex]\(63 \pi\)[/tex] in.

Sagot :

To find the length of the minor arc SV in circle [tex]\( T \)[/tex] with radius 24 inches and central angle [tex]\(\theta = \frac{5\pi}{6}\)[/tex] radians, we use the formula for arc length:

[tex]\[ \text{Arc Length} = \theta \times \text{Radius} \][/tex]

Step-by-step, let's proceed:

1. Identify the given values:
- Radius, [tex]\( r = 24 \)[/tex] inches
- Central angle, [tex]\( \theta = \frac{5\pi}{6} \)[/tex] radians

2. Substitute the values into the formula:

[tex]\[ \text{Arc Length} = \frac{5\pi}{6} \times 24 \][/tex]

3. Multiply the constants:

[tex]\[ \text{Arc Length} = \frac{5\pi}{6} \times 24 = 20\pi \][/tex]

So, the length of the minor arc SV is:

[tex]\[ 20\pi \text{ inches} \][/tex]

This matches one of the given options.

[tex]\[ \boxed{20\pi} \][/tex]