Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

An antique wooden chest has the shape of a rectangular prism. It has a width of 16 inches. Its length is 4 times its height. The volume of the chest is 4,096 cubic inches. What is the height of the chest?

A. [tex]$\pm 8$[/tex]
B. [tex]$-8$[/tex]
C. 8
D. 64

Sagot :

To solve for the height of the chest, we need to use the given information and the formula for the volume of a rectangular prism.

1. Given Information:
- Width ([tex]\(w\)[/tex]) of the chest: 16 inches
- Volume ([tex]\(V\)[/tex]) of the chest: 4096 cubic inches
- Length ([tex]\(l\)[/tex]) is 4 times the height ([tex]\(h\)[/tex])

2. Formulation:
- The volume [tex]\(V\)[/tex] of a rectangular prism is given by:
[tex]\[ V = l \times w \times h \][/tex]
- According to the problem, the length [tex]\(l\)[/tex] is [tex]\(4 \times h\)[/tex]. Therefore, the equation becomes:
[tex]\[ V = (4h) \times 16 \times h \][/tex]
- Substitute the given volume, 4096 cubic inches:
[tex]\[ 4096 = 4h \times 16 \times h \][/tex]

3. Simplification:
- Simplifying inside the equation:
[tex]\[ 4096 = 64h^2 \][/tex]
- Divide both sides by 64 to isolate [tex]\(h^2\)[/tex]:
[tex]\[ h^2 = \frac{4096}{64} \][/tex]
[tex]\[ h^2 = 64 \][/tex]

4. Solving for [tex]\(h\)[/tex]:
- Take the square root of both sides to solve for [tex]\(h\)[/tex]:
[tex]\[ h = \sqrt{64} \][/tex]
- Considering both positive and negative solutions:
[tex]\[ h = \pm 8 \][/tex]

Given that a physical dimension like height must be a positive value, we discard the negative solution.

Therefore, the height of the chest is:
[tex]\[ \boxed{8} \][/tex]