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Complete the remainder of the table for the given function rule:

[tex]\[ y=\frac{x}{2}+5 \][/tex]

\begin{tabular}{l|lllll}
x & -4 & -2 & 0 & 2 & 4 \\
\hline
y & 3 & [?] & [?] & [?] & [?] \\
\end{tabular}


Sagot :

Certainly! Let's complete the rest of the table step-by-step for the given function rule [tex]\( y = \frac{x}{2} + 5 \)[/tex]:

1. For [tex]\( x = -4 \)[/tex]:
[tex]\[ y = \frac{-4}{2} + 5 = -2 + 5 = 3 \][/tex]
So for [tex]\( x = -4 \)[/tex], [tex]\( y = 3 \)[/tex].

2. For [tex]\( x = -2 \)[/tex]:
[tex]\[ y = \frac{-2}{2} + 5 = -1 + 5 = 4 \][/tex]
So for [tex]\( x = -2 \)[/tex], [tex]\( y = 4 \)[/tex].

3. For [tex]\( x = 0 \)[/tex]:
[tex]\[ y = \frac{0}{2} + 5 = 0 + 5 = 5 \][/tex]
So for [tex]\( x = 0 \)[/tex], [tex]\( y = 5 \)[/tex].

4. For [tex]\( x = 2 \)[/tex]:
[tex]\[ y = \frac{2}{2} + 5 = 1 + 5 = 6 \][/tex]
So for [tex]\( x = 2 \)[/tex], [tex]\( y = 6 \)[/tex].

5. For [tex]\( x = 4 \)[/tex]:
[tex]\[ y = \frac{4}{2} + 5 = 2 + 5 = 7 \][/tex]
So for [tex]\( x = 4 \)[/tex], [tex]\( y = 7 \)[/tex].

Now we fill in the values in the table:

\begin{tabular}{l|lllll}
x & -4 & -2 & 0 & 2 & 4 \\
\hline
y & 3 & 4 & 5 & 6 & 7 \\
\end{tabular}

These are the completed values for the table based on the function rule [tex]\( y = \frac{x}{2} + 5 \)[/tex].