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20. En el interior de un cuadrado PQRS se construye un triángulo rectángulo PFS tomando PS como hipotenusa. Por F se traza una paralela a PQ que corta a PS y QR en H y T respectivamente.
La prolongación de QR con la de PF se cortan en U.
"Hallar TU" si PF = 3√/13; PH = 9.
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